So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}
2. Which greatest possible length can be used to measure exactly 15 meter 75 cm, 11 meter 25 cm and 7 meter 65 cm
45cm
255cm
244cm
55cm
Answer: Option A
Explanation:
Convert first all terms into cm.
i.e. 1575 cm, 1125cm, 765cm.
Now whenever we need to calculate this type of question, we need to find the HCF. HCF of above terms is 255.
3. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}
128
126
146
434
Answer: Option B
Explanation:
HCF is Highest common factor, so we need to get the common highest factors among given values. So we got
2 * 3*3 * 7
4. There are three numbers, these are co-prime to each other are such that the product of the first two is 551 and that of the last two is 1073. What will be the sum of three numbers :
80
82
85
87
Answer: Option C
Explanation:
As given the questions these numbers are co primes, so there is only 1 as their common factor. It is also given that two products have the middle number in common. So, middle number = H.C.F. of 551 and 1073 = 29;
So first number is : 551/29 = 19 Third number = 1073/29 = 37
So sum of these numbers is = (19 + 29 + 37) = 85
5. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
48
22
56
27
Answer: Option A
Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.