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Question Detail
What will be the LCM of 8, 24, 36 and 54
- 54
- 108
- 216
- 432
Answer: Option C
Explanation:
LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216
1. Find the largest number which divides 62,132,237 to leave the same reminder
- 30
- 32
- 35
- 45
Answer: Option C
Explanation:
Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35
2. The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number
- 400
- 256
- 120
- 420
Answer: Option D
Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 12 * 5040
x = (12*5040)/144 = 420
3. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.
- 15
- 16
- 30
- 31
Answer: Option D
Explanation:
LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.
Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31
4. An electronic device makes a beep after every 60 sec. Another device makes a beep after every 62 sec. They beeped together at 10 a.m. The time when they will next make a beep together at the earliest, is
- 10:28 am
- 10:30 am
- 10:31 am
- None of above
Answer: Option C
Explanation:
L.C.M. of 60 and 62 seconds is 1860 seconds
1860/60 = 31 minutes
They will beep together at 10:31 a.m.
Sometimes questions on red lights blinking comes in exam, which can be solved in the same way
5. Find the HCF of 23,46,827
- 227
- 83
- 23
- 827
Answer: Option A
Explanation:
Whenever we have to solve this sort of question, remember the formula.
HCF = HCFofNumeratorsLCMofDenominators
So answers will be option 1
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