What will be the fraction of 4%

Answer: Option C

Explanation:

Failed in mathematics, n(A) = 34
Failed in English, n(B) = 42
$$\begin{aligned} n(A\cup B) = n(A)+n(B)-n(A\cap B) \\ = 34+42-20 = 56 \\ \text{Failed in either or both subjects are 56} \\ \text{Percentage passed = }(100-56)\% \\ = 44\% \end{aligned}$$

Answer: Option C

Explanation:

It is , y% of z = 2(x% of y)
=> yz/100 = 2xy/100
=> z = 2x

Answer: Option A

Explanation:

Let the total number of votes enrolled are x.
Number of votes cast = 75% of x
Valid votes = 98% of 75% of x

Now, as 9261 is the 75% of valid casted votes so,

75% of 98% of 75% of x = 9261 [imporant]

$$\begin{align} => \frac{75 \times 98 \times 75 \times x}{100 \times 100 \times 100} = 9261 \\ => x = 16800 \end{align}$$

Answer: Option C

Explanation:

Total number of votes polled = (1136 + 7636 + 11628) = 20400

So, Required percentage = 11628/20400 * 100 = 57%

Answer: Option D

Explanation:

It means that 0.08% of x = 2
$$\begin{aligned} => ( \frac{8}{100 \times 100} \times x) = 2 \\ => x = \frac{2 \times 100 \times 100}{8} \\ => x = 2500 \end{aligned}$$