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Question Detail
What will be the difference between simple and compound interest @ 10% per annum on the sum of Rs 1000 after 4 years
- Rs 62.10
- Rs 63.10
- Rs 64.10
- Rs 65.10
Answer: Option C
Explanation:
S.I.=1000∗10∗4100=400C.I.=[1000(1+10100)4−1000]=464.10
So difference between simple interest and compound interest will be 464.10 - 400 = 64.10
1. What will be the difference between simple and compound interest @ 10% per annum on the sum of Rs 1000 after 4 years
- Rs 62.10
- Rs 63.10
- Rs 64.10
- Rs 65.10
Answer: Option C
Explanation:
S.I.=1000∗10∗4100=400C.I.=[1000(1+10100)4−1000]=464.10
So difference between simple interest and compound interest will be 464.10 - 400 = 64.10
2. On a sum of money, simple interest for 2 years is Rs 660 and compound interest is Rs 696.30, the rate of interest being the same in both cases.
- 8%
- 9%
- 10%
- 11%
Answer: Option D
Explanation:
Difference between C.I and S.I for 2 years = 36.30
S.I. for one year = 330.
S.I. on Rs 330 for one year = 36.30
So R% = \frac{100*36.30}{330*1} = 11%
3. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum
- Rs 600
- Rs 625
- Rs 650
- Rs 675
Answer: Option B
Explanation:
Let the Sum be P
S.I.=P∗4∗2100=2P25C.I.=P(1+4100)2−P=676P625−P=51P625As, C.I. - S.I = 1=>51P625−2P25=1=>51P−50P625=1P=625
4. In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually
- 2 Years
- 3 Years
- 4 Years
- 5 Years
Answer: Option B
Explanation:
Principal = Rs.1000;
Amount = Rs.1331;
Rate = Rs.10%p.a.
Let the time be n years then,
1000(1+10100)n=1331(1110)n=13311000(1110)3=13311000
So answer is 3 years
5. A sum of money invested at compound interest to Rs. 800 in 3 years and to Rs 840 in 4 years. The rate on interest per annum is.
- 4%
- 5%
- 6%
- 7%
Answer: Option B
Explanation:
S.I. on Rs 800 for 1 year = 40
Rate = (100*40)/(800*1) = 5%
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