Question Detail

What least value should be replaced by * in 223*431 so the number become divisible by 9

  • 3
  • 4
  • 5
  • 6

Answer: Option A

Explanation:

Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (2+2+3+*+4+3+1) = 15+* should be divisible by 9,
15+3 will be divisible by 9,
so that least number is 3.
Similar Questions :

1. 1939392 * 625

  • 1212120010
  • 1212120000
  • 1212120011
  • 1212121010

Answer: Option B

Explanation:

Trick: when multiplying with \begin{aligned} 5^n
\end{aligned} then put n zeros to the right of multiplicand and divide the number with \begin{aligned} 2^n
\end{aligned}
So using this we can solve this question in much less
time.
\begin{aligned} 1939392 \times 5^4 = \frac {19393920000}{16} = 1212120000
\end{aligned}

2. 6897 is divisible by

  • 11 only
  • 19 only
  • both 11 and 19
  • neither 11 nor 19

Answer: Option C

3. A number when divided by 44, gives 432 as quotient and 0 as remainder. What will be the remainder when dividing the same number by 31

  • 5
  • 3
  • 4
  • 6

Answer: Option A

Explanation:

P ÷ 44 = 432

=> P = 432 * 44 = 19008

P / 31 = 19008 / 31 = 613, remainder = 5

4. 7589 - X = 3434

  • 4155
  • 2321
  • 3155
  • None of above

Answer: Option A

5. What least number must be subtracted from 427398 so that remaining number is divisible by 15

  • 3
  • 5
  • 7
  • 9

Answer: Option A

Explanation:

On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted

Read more from - Numbers Questions Answers