Question Detail

What is the unit digit in
\begin{aligned}
(6324)^{1797} \times (615)^{316} \times (341)^{476}
\end{aligned}

Answer: Option D

1. What is the unit digit in
\begin{aligned}
(6324)^{1797} \times (615)^{316} \times (341)^{476}
\end{aligned}

Answer: Option D

2. Find the unit digit in \begin{aligned}
(544)^{102} + (544)^{103}
\end{aligned}

Answer: Option C

Explanation:

Required digit is = \begin{aligned}
(4)^{102} + (4)^{103} \end{aligned}
as \begin{aligned} (4)^2 \end{aligned} gives unit digit 6 so \begin{aligned} (4)^{102} \end{aligned} unit digit is 6 and \begin{aligned} (4)^{103} \end{aligned} unit digit is, unit digit of \begin{aligned} 6 \times 4 \end{aligned}= 4, so answer will be unit digit of 6 + 4 = 0

3. What least number should be added to 1056, so that the sum is completely divisible by 23

Answer: Option C

Explanation:

(1056 / 23) gives remainder 21

21 + 2 = 23, So we need to add 2

4. 6897 is divisible by

11 only
19 only
both 11 and 19
neither 11 nor 19

Answer: Option C

5. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}

Answer: Option D

Question Detail

What is the unit digit in \begin{aligned} (6324)^{1797} \times (615)^{316} \times (341)^{476} \end{aligned}

1. What is the unit digit in \begin{aligned} (6324)^{1797} \times (615)^{316} \times (341)^{476} \end{aligned}

2. Find the unit digit in \begin{aligned} (544)^{102} + (544)^{103} \end{aligned}

3. What least number should be added to 1056, so that the sum is completely divisible by 23

4. 6897 is divisible by

5. \begin{aligned} 46^2 - (?)^2 = 4398 - 3066 \end{aligned}

What is the unit digit in
\begin{aligned}
(6324)^{1797} \times (615)^{316} \times (341)^{476}
\end{aligned}

1. What is the unit digit in
\begin{aligned}
(6324)^{1797} \times (615)^{316} \times (341)^{476}
\end{aligned}

2. Find the unit digit in \begin{aligned}
(544)^{102} + (544)^{103}
\end{aligned}

5. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}