Question Detail

What is the largest 4 digit number exactly divisible by 88

9900
9999
9988
9944

Answer: Option D

Explanation:

Largest 4 digit number is 9999
After doing 9999 ÷ 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944

1. What least number must be subtracted from 427398 so that remaining number is divisible by 15

Answer: Option A

Explanation:

On dividing 427398 by 15 we get the remainder 3, so 3 should be subtracted

2. 7589 - X = 3434

4155
2321
3155
None of above

Answer: Option A

3. 217 * 217 + 183 * 183

70578
82578
80578
80568

Answer: Option C

Explanation:

\begin{aligned}
\frac {1}{2}\times 2(a^2 + b^2) = \frac {1}{2} \times [(a + b)^2 + (a - b)^2]
\end{aligned}
\begin{aligned}
= \frac {1}{2} \times [(217 + 183)^2 + (217 - 183)^2] = 80578
\end{aligned}

4. 6897 is divisible by

11 only
19 only
both 11 and 19
neither 11 nor 19

Answer: Option C

5. For the integer n, if nnn is odd, then what is true

n is odd and n*n is even
n*n is odd
n is even
n*n is odd

Answer: Option A

Question Detail

What is the largest 4 digit number exactly divisible by 88

1. What least number must be subtracted from 427398 so that remaining number is divisible by 15

2. 7589 - X = 3434

3. 217 * 217 + 183 * 183

4. 6897 is divisible by

5. For the integer n, if n*n*n is odd, then what is true

5. For the integer n, if nnn is odd, then what is true