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Question Detail
What is the largest 4 digit number exactly divisible by 88
- 9900
- 9999
- 9988
- 9944
Answer: Option D
Explanation:
Largest 4 digit number is 9999
After doing 9999 ÷ 88 we get remainder 55
Hence largest 4 digit number exactly divisible by 88 = 9999 - 55 = 9944
1. What least value should be replaced by * in 223*431 so the number become divisible by 9
- 3
- 4
- 5
- 6
Answer: Option A
Explanation:
Trick: Number is divisible by 9, if sum of all digits is divisible by 9, so (2+2+3+*+4+3+1) = 15+* should be divisible by 9,
15+3 will be divisible by 9,
so that least number is 3.
2. 587 * 999 = ?
- 586411
- 586413
- 486411
- 486413
Answer: Option B
Explanation:
Trick: 587 * (1000 - 1) = 587000 - 587 = 586413
3. 1939392 * 625
- 1212120010
- 1212120000
- 1212120011
- 1212121010
Answer: Option B
Explanation:
Trick: when multiplying with \begin{aligned} 5^n
\end{aligned} then put n zeros to the right of multiplicand and divide the number with \begin{aligned} 2^n
\end{aligned}
So using this we can solve this question in much less
time.
\begin{aligned} 1939392 \times 5^4 = \frac {19393920000}{16} = 1212120000
\end{aligned}
4. \begin{aligned}
46^2 - (?)^2 = 4398 - 3066
\end{aligned}
- 23
- 18
- 38
- 28
Answer: Option D
5. All prime numbers are odd numbers
- True
- False
Answer: Option B
Explanation:
It is false, 2 is an even number
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