- Home
- Quantitative
- English
- Reasoning
- IT Officer
- Programming
-
Computer
- Computer Awareness Questions Answers - Set 1
- Computer Awareness Questions Answers - Set 2
- Important Abbreviations Computer Awareness Questions Answers
- Important File Extensions Questions Answers
- Computer System Architecture Questions Answers
- MS Office Questions Answers
- MS Excel Questions Answers
- MS PowerPoint Questions Answers
-
GK
- Geography Questions Answers
- Indian History Questions Answers
- World History Questions Answers
- Indian Economy Questions Answers
- Indian Polity and Constitution
- Physics Questions Answers
- Chemistry Questions Answers
- Biology Questions Answers
- First In India
- First In World
- Longest and Largest
- Books and Authors
- Important Days of year
- Countries and Capitals
- Inventions and Inventors
-
Current Affairs
- Current Affairs
- Current Affairs 2018
- Current Affairs 2018 - 2019 PDF
- Current Affairs August 2019
- Current Affairs July 2019
- Current Affairs June 2019
- Current Affairs May 2019
- Current Affairs April 2019
- Current Affairs March 2019
- Current Affairs February 2019
- Current Affairs January 2019
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Govt Jobs
- Exams
- Online Quiz
- You are here
- Home
- Quantitative Aptitude
- Arithmetic Aptitude Questions Answers
- Area Questions Answers
- Aptitude Question
- Current Affairs 2019
- Current Affairs 2018
- Current Affairs December 2018
- Current Affairs November 2018
- Current Affairs October 2018
- Current Affairs September 2018
- Current Affairs August 2018
- Current Affairs July 2018
- Current Affairs June 2018
- Current Affairs May 2018
- Current Affairs April 2018
- Current Affairs March 2018
- Current Affairs February 2018
- Current Affairs January 2018
- Current Affairs 2018
- Current Affairs PDF
- Current Affairs PDF Download
- Current Affairs July 2019 PDF
- Current Affairs June 2019 PDF
- Current Affairs May 2019 PDF
- Current Affairs April 2019 PDF
- Current Affairs March 2019 PDF
- Current Affairs February 2019 PDF
- Current Affairs January 2019 PDF
- Current Affairs December 2018 PDF
- Current Affairs November 2018 PDF
- Current Affairs October 2018 PDF
- Current Affairs September 2018 PDF
- Current Affairs August 2018 PDF
- Current Affairs July 2018 PDF
- Current Affairs June 2018 PDF
- Current Affairs May 2018 PDF
- Current Affairs April 2018 PDF
- Current Affairs March 2018 PDF
- Current Affairs February 2018 PDF
- Current Affairs January 2018 PDF
Question Detail
What are the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad ?
- 714
- 814
- 850
- 866
Answer: Option B
Explanation:
In this type of questions, first we need to calculate the area of tiles. With we can get by obtaining the length of largest tile.
Length of largest tile can be obtained from HCF of length and breadth.
So lets solve this,
Length of largest tile = HCF of (1517 cm and 902 cm)
= 41 cm
Required number of tiles =
\begin{aligned}
\frac{\text{Area of floor}}{\text{Area of tile}} \\
= \left(\frac{1517\times902}{41 \times 41}\right)\\
= 814
\end{aligned}
1. 50 square stone slabs of equal size were needed to cover a floor area of 72 sq.m. Find the length of each stone slab.
- 110 cm
- 116 cm
- 118 cm
- 120 cm
Answer: Option D
Explanation:
Area of each slab =
\begin{aligned}
\frac{72}{50}m^2 = 1.44 m^2\\
\text{Length of each slab =}\sqrt{1.44} \\
= 1.2m = 120 cm
\end{aligned}
2. The area of incircle of an equilateral triangle of side 42 cm is :
- \begin{aligned} 462 cm^2 \end{aligned}
- \begin{aligned} 452 cm^2 \end{aligned}
- \begin{aligned} 442 cm^2 \end{aligned}
- \begin{aligned} 432 cm^2 \end{aligned}
Answer: Option A
Explanation:
\begin{aligned}
\text{Radius of incircle} = \frac{a}{2\sqrt3} \\
= \frac{42}{2\sqrt3} \\
= 7\sqrt{3} \\
\text{Area of incircle =} \\
\frac{22}{7}*49*3 = 462 cm^2
\end{aligned}
3. A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the parallelogram is 100 m , then the altitude of the triangle is.
- 200 m
- 150 m
- 148 m
- 140 m
Answer: Option A
Explanation:
Let the triangle and parallelogram have common base b,
let the Altitude of triangle is h1 and of parallelogram is h2(which is equal to 100 m), then
\begin{aligned}
\text{Area of triangle =}\frac{1}{2}*b*h1\\
\text{Area of rectangle =}b*h2\\
\text{As per question }\\
\frac{1}{2}*b*h1 = b*h2 \\
\frac{1}{2}*b*h1 = b*100 \\
h1 = 100*2 = 200 m \\
\end{aligned}
4. One side of rectangular field is 15 meter and one of its diagonals is 17 meter. Then find the area of the field.
- \begin{aligned} 120m^2 \end{aligned}
- \begin{aligned} 130m^2 \end{aligned}
- \begin{aligned} 140m^2 \end{aligned}
- \begin{aligned} 150m^2 \end{aligned}
Answer: Option A
Explanation:
\begin{aligned}
\text{We know }h^2 = b^2+h^2 \\
=>\text{Other side }= \sqrt{(17)^2-(15)^2} \\
= \sqrt{289-225} = \sqrt{64} \\
= 8 meter \\
Area = Length \times Breadth \\
= 15\times8 m^2 = 120 m^2
\end{aligned}
5. A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered.If the area of the field is 680 sq.ft, how many feet of fencing will be required ?
- 88 feet
- 86 feet
- 84 feet
- 82 feet
Answer: Option A
Explanation:
We are given with length and area, so we can find the breadth.
as Length * Breadth = Area
=> 20 * Breadth = 680
=> Breadth = 34 feet
Area to be fenced = 2B + L = 2*34 + 20
= 88 feet
Thanks ! Your comment will be approved shortly !
- Copyright 2014 - All rights reserved
- Terms Of Use & Privacy Policy
- Contact Us
- Copyright