Question Detail
Value of
\begin{aligned}
\frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}
\end{aligned}
- \begin{aligned} \frac{6}{19} \end{aligned}
- \begin{aligned} \frac{7}{19} \end{aligned}
- \begin{aligned} \frac{8}{19} \end{aligned}
- \begin{aligned} \frac{9}{19} \end{aligned}
Answer: Option C
Explanation:
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{1}{\frac{3}{2}}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{2}{3}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{\frac{8}{3}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{3}{8}}
\end{aligned}
\begin{aligned}
= \frac{1}{\frac{19}{8}}
\end{aligned}
\begin{aligned}
= \frac{8}{19}
\end{aligned}