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Question Detail
The sum of three numbers is 98. If the ratio of the first to the second is 2:3 and that of the second to the third is 5:8, then the second number is
- 10
- 17
- 25
- 30
Answer: Option D
Explanation:
\begin{aligned}
a:b = 2:3 \\
b:c = 5:8 = (5*\frac{3}{5} : 8*\frac{3}{5}) \\
= 3:\frac{24}{5} \\
a:b:c = 2:3:\frac{24}{5} \\
= 10:15:24 \\
b = 98*\frac{15}{49} \\
= 30
\end{aligned}
1. If 2 : 9 :: x : 18, then find the value of x
- 2
- 3
- 4
- 6
Answer: Option C
Explanation:
Treat 2:9 as 2/9 and x:18 as x/18, treat :: as =
So we get 2/9 = x/18
=> 9x = 36
=> x = 4
2. Rs. 120 are divided among A, B, C such that A's share is Rs. 20 more than B's and Rs. 20 less than C's. What is B's share
- Rs 10
- Rs 20
- Rs 24
- Rs 28
Answer: Option B
Explanation:
Let C = x. Then A = (x—20) and B = (x—40).
x + x - 20 + x - 40 = 120 Or x=60.
A:B:C = 40:20:60 = 2:1 :3.
B's share = Rs. 120*(1/6) = Rs. 20
3. The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a ratio less than 16 : 21, is
- 3
- 4
- 5
- 6
Answer: Option A
Explanation:
Let x is subtracted.
Then,
\begin{aligned}
\frac{(6-x)}{(7-x)}< \frac{16}{21} \\
21(6—x) < 16(7—x)\\
=> 5x > 14 = x > 2.8
\end{aligned}
Least such number is 3
4. if x:y = 1:3, then find the value of
(7x+3y):(2x+y)
- 14:5
- 15:5
- 16:5
- 17:5
Answer: Option C
Explanation:
let x = 1k and y = 3k, so
\begin{aligned}
= \frac{7(k)+3(3k)}{2(k)+1(3k)} \\
= \frac{16k}{5k} \\
= 16:5
\end{aligned}
5. If three numbers in the ratio 3 : 2: 5 be such that the sum of their squares is 1862, the middle number will be
- 10
- 14
- 18
- 22
Answer: Option B
Explanation:
Let the numbers be 3x, 2x and 5x.
Then,
9x + 4x + 25x =1862
⇒ 38x = 1862
⇒ x = 49 ⇒ x = 7.
middle number = 2x = 14
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