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Question Detail
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
- 15 years
- 18 years
- 20 years
- 22 years
Answer: Option C
Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
1. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present
- 25
- 30
- 45
- 60
Answer: Option B
Explanation:
Let their ages 10 years ago is x, 2x and 3x years.
10 + 2x + 10 + 3x + 10 = 90 hence x= 10
B’s present age = (2x + 10) =30 years
2. The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
- 15
- 20
- 25
- 30
Answer: Option D
Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
3. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
4. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages
- 35
- 34
- 45
- 25
Answer: Option A
Explanation:
Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
5. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son
- 34,11
- 35,10
- 36,9
- 40,5
Answer: Option C
Explanation:
Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.
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