Navigate

Question Detail

The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is

  • 48
  • 22
  • 56
  • 27

Answer: Option A

Explanation:

Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.

Similar Questions :

1. Reduce \begin{aligned}
\frac{803}{876}
\end{aligned} to the lowest terms.

  • \begin{aligned} \frac{11}{12} \end{aligned}
  • \begin{aligned} \frac{23}{24} \end{aligned}
  • \begin{aligned} \frac{26}{27} \end{aligned}
  • \begin{aligned} \frac{4}{7} \end{aligned}

Answer: Option A

Explanation:

HCF of 803 and 876 is 73, Divide both by 73, We get the answer 11/12

2. Find the largest number which divides 62,132,237 to leave the same reminder

  • 30
  • 32
  • 35
  • 45

Answer: Option C

Explanation:

Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35

3. The greatest possible length which can be used to measure exactly the lengths 7 m, 3 m 85 cm, 12 m 95 cm is

  • 16cm
  • 25cm
  • 15cm
  • 35cm

Answer: Option D

Explanation:

So by now, you must be knowing this is a question of HCF, right.
H.C.F. of (700 cm, 385 cm, 1295 cm) = 35 cm.

4. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other

  • 34
  • 77
  • 12
  • 45

Answer: Option B

Explanation:

For any this type of question, remember
Product of two numbers = Product of their HCF and LCM

So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77

5. Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

  • 15
  • 16
  • 30
  • 31

Answer: Option D

Explanation:

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.

Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31

Read more from - HCF and LCM Questions Answers