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The number of girls in a class are 7 times the number of boys, which value can never be the of total students

  • 40
  • 48
  • 24
  • 30

Answer: Option D

Explanation:

Let the boys are X, then girls are 7X, total = X+7X = 8X

So it should be multiple of 8, 30 is not a multiple of 8.

Similar Questions :

1. 3640 ÷ 14*16 + 340 = ?

  • 3500
  • 4500
  • 1500
  • 2500

Answer: Option B

2. 7500 + (1250 / 50)

  • 7500
  • 7525
  • 7550
  • 8000

Answer: Option B

Explanation:

As per BODMAS rule first we will solve the terms in the bracket then other.
= 7500 + (25) = 7525

3. 3034 - (1002 / 20.04) = ?

  • 2984
  • 2983
  • 2982
  • 2981

Answer: Option A

4. Simplify
\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} } \div 5.25
\end{aligned}

  • \begin{aligned} \frac{3}{5} \end{aligned}
  • \begin{aligned} \frac{3}{6} \end{aligned}
  • \begin{aligned} \frac{3}{7} \end{aligned}
  • \begin{aligned} \frac{3}{8} \end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
\frac{\frac{7}{2}\div {\frac{5}{2}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{5}{2}} of \frac{3}{2} }\div 5.25
\end{aligned}

\begin{aligned}
= \frac{\frac{7}{2}\times {\frac{2}{5}} \times {\frac{3}{2}} }{\frac{7}{2} \div { \frac{15}{4}}}\div 5.25
\end{aligned}

\begin{aligned}
= \frac{\frac{21}{10}}
{\frac{7}{2} \times { \frac{4}{15}}}\div {\frac{525}{100}}
\end{aligned}

\begin{aligned}
= \frac{21}{10}\times{\frac{15}{14}}\times\frac{100}{525}

= \frac{6}{14}
= \frac{3}{7}
\end{aligned}

5. a * b = 2a - 3b + ab, then 3*5 + 5*3 = ?

  • 20
  • 21
  • 22
  • 23

Answer: Option C

Explanation:

= 2(3)-3(5)+(3*5) + 2(5)-3(3)+(5*3)
= 6-15+15+10-9+15 = 31-9 = 22

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