Question Detail

The number of girls in a class are 7 times the number of boys, which value can never be the of total students

Answer: Option D

Explanation:

Let the boys are X, then girls are 7X, total = X+7X = 8X

So it should be multiple of 8, 30 is not a multiple of 8.

1. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

1964
1984
2964
2984

Answer: Option D

Explanation:

$\begin{aligned} = 3034 -( \frac{1002}{2004} \times 100) \end{aligned}$

$\begin{aligned} = 3034 - 50 = 2984 \end{aligned}$

2. How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

Answer: Option C

Explanation:

We need so simple divide 42.5/0.85,
=(4250/85) = 50

3. Simplify
$\begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}$

Answer: Option B

Explanation:

$\begin{aligned} = 16-[5-(6+2(7-8+5))] \end{aligned}$
(Please check due to overline, sign has been changed)

$\begin{aligned} = 16-[5-(6+2 \times 4))] \end{aligned}$

$\begin{aligned} = 16-[-9] = 16 + 9 = 25 \end{aligned}$

4. 5004 / 139 - 6

Answer: Option D

5. $\begin{aligned} \frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 } \end{aligned}$

7.50
7.75
8
8.05

Answer: Option B

Explanation:

$\begin{aligned} \frac{4+72-6-8}{738-730} \end{aligned}$

$\begin{aligned} = \frac{76-14}{8} \end{aligned}$

$\begin{aligned} = \frac{62}{8} = 7.75 \end{aligned}$

Question Detail

The number of girls in a class are 7 times the number of boys, which value can never be the of total students

1. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

2. How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

3. Simplify
$\begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}$

4. 5004 / 139 - 6

5. $\begin{aligned} \frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 } \end{aligned}$

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Question Detail

The number of girls in a class are 7 times the number of boys, which value can never be the of total students

1. 3034−(1002÷20.04)=?\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}

2. How many pieces of 0.85 meteres can be cut from a rod 42.5 meteres long

3. Simplify 16−[5−(6+2(7−¯8−5))]\begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}

4. 5004 / 139 - 6

5. 4+4×18−6−8123×6−146×5\begin{aligned} \frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 } \end{aligned}

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1. $\begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}$

3. Simplify
$\begin{aligned} 16-[5-(6+2(7-\overline{8-5}))] \end{aligned}$

5. $\begin{aligned} \frac{4+4 \times 18 -6 - 8}{123 \times 6 - 146 \times 5 } \end{aligned}$