Question Detail

The least perfect square, which is divisible by each of 21, 36 and 66 is

213414
213424
213434
213444

Answer: Option D

Explanation:

L.C.M. of 21, 36, 66 = 2772

Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11

To make it a perfect square, it must be multiplied by 7 x 11.

So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444

1. Find the value of x
$\begin{aligned} \frac{2707}{\sqrt{x}} = 27.07 \end{aligned}$

1000
10000
10000000
None of above

Answer: Option B

Explanation:

$\begin{aligned} = \frac{2707}{27.07} = \sqrt{x} \end{aligned}$

$\begin{aligned} => \frac{2707 \times 100}{2707} = \sqrt{x} \end{aligned}$

$\begin{aligned} => 100 = \sqrt{x} \end{aligned}$

$\begin{aligned} => x = 100^2 = 10000 \end{aligned}$

2. $\begin{aligned} \sqrt{\frac{0.081 * 0.484 }{0.0064 * 6.25}} \end{aligned}$

0.66
0.77
0.88
0.99

Answer: Option D

3. $\begin{aligned} (\frac{\sqrt{625}}{11} \times \frac{14}{\sqrt{25}} \times \frac{11}{\sqrt{196}}) \end{aligned}$

Answer: Option C

Explanation:

$\begin{aligned} = (\frac{25}{11} \times \frac{14}{5} \times \frac{11}{14}) \end{aligned}$

$\begin{aligned} = 5 \end{aligned}$

4. The cube root of .000216 is

0.6
0.006
0.06
.0006

Answer: Option C

5. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

Answer: Option C

Explanation:

So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
$\begin{aligned} \text{Total Members = } \sqrt{5929} \\ = 77 \end{aligned}$