Question Detail

The largest four digit number which is a perfect cube, is:

  • 7000
  • 8000
  • 9261
  • 9999

Answer: Option C

Explanation:

21*21*21 = 9261
Similar Questions :

1. if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

  • 12.039
  • 1.2039
  • 11.039
  • 1.1039

Answer: Option D

Explanation:

Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :

\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}

\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= (1-2a) + 3a \end{aligned}

\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}



2. The cube root of .000216 is

  • 0.6
  • 0.006
  • 0.06
  • .0006

Answer: Option C

3. Evaluate
\begin{aligned}
\sqrt{6084}
\end{aligned}

  • 75
  • 77
  • 78
  • 68

Answer: Option C

4. What is the square root of 0.16

  • 0.4
  • 0.04
  • 0.004
  • 4

Answer: Option A

Explanation:

as .4 * .4 = 0.16

5. The least perfect square, which is divisible by each of 21, 36 and 66 is

  • 213414
  • 213424
  • 213434
  • 213444

Answer: Option D

Explanation:

L.C.M. of 21, 36, 66 = 2772

Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11

To make it a perfect square, it must be multiplied by 7 x 11.

So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444

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