Question Detail

The largest four digit number which is a perfect cube, is:

7000
8000
9261
9999

Answer: Option C

Explanation:

21*21*21 = 9261

1. \begin{aligned} \sqrt{0.00059049} \end{aligned}

24.3
2.43
0.243
0.0243

Answer: Option D

2. Evaluate
\begin{aligned} \sqrt[3]{4\frac{12}{125}} \end{aligned}

\begin{aligned} 1\frac{2}{5} \end{aligned}
\begin{aligned} 1\frac{3}{5} \end{aligned}
\begin{aligned} 1\frac{4}{5} \end{aligned}
1

Answer: Option B

Explanation:

\begin{aligned}
= \sqrt[3]{\frac{512}{125}} \end{aligned}
\begin{aligned}
= (\frac{8*8*8}{5*5*5})^{\frac{1}{3}} \end{aligned}

\begin{aligned} = \frac{8}{5} = 1\frac{3}{5} \end{aligned}

3. Find the value of x
\begin{aligned}
\frac{2707}{\sqrt{x}} = 27.07
\end{aligned}

1000
10000
10000000
None of above

Answer: Option B

Explanation:

\begin{aligned}
= \frac{2707}{27.07} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> \frac{2707 \times 100}{2707} = \sqrt{x}
\end{aligned}

\begin{aligned}
=> 100 = \sqrt{x}
\end{aligned}

\begin{aligned}
=> x = 100^2 = 10000
\end{aligned}

4. \begin{aligned}
\sqrt{41 - \sqrt{21 + \sqrt{19 - \sqrt{9}}}}
\end{aligned}

Answer: Option D

Explanation:

\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{19 - 3}}}
\end{aligned}

\begin{aligned}
= \sqrt{41 - \sqrt{21 + \sqrt{16}}}
\end{aligned}

\begin{aligned}
= \sqrt{41 - \sqrt{21 + 4}}
\end{aligned}

\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}

\begin{aligned}
= \sqrt{41 - \sqrt{25}}
\end{aligned}

\begin{aligned}
= \sqrt{41 - 5}
\end{aligned}

\begin{aligned}
= \sqrt{36} = 6
\end{aligned}

5. Students of a class collected as many paise from each student of class as is the number of students in that class. If total collection is Rs. 59.29, then find the total number of students in the class.

Answer: Option C

Explanation:

So from the question it is clear that total sum collected was 59.29 rupees.
So total paise are 5929.
\begin{aligned}
\text{Total Members = } \sqrt{5929} \\
= 77
\end{aligned}