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Question Detail
The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number
- 400
- 256
- 120
- 420
Answer: Option D
Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 12 * 5040
x = (12*5040)/144 = 420
1. Find the LCM of \begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}
- \begin{aligned} \frac{2}{27} \end{aligned}
- \begin{aligned} \frac{8}{3} \end{aligned}
- \begin{aligned} \frac{2}{3} \end{aligned}
- \begin{aligned} \frac{8}{27} \end{aligned}
Answer: Option B
Explanation:
Whenever we have to solve this sort of question, remember the formula.
LCM = \\begin{aligned} \\frac{HCF of Denominators}{LCM of Numerators} \\end{aligned}
So answers will be option 2,
Please also give attention to the difference in formula of HCF and LCM
2. If LCM of two number is 693, HCF of two numbers is 11 and one number is 99, then find other
- 34
- 77
- 12
- 45
Answer: Option B
Explanation:
For any this type of question, remember
Product of two numbers = Product of their HCF and LCM
So Other number = \begin{aligned} \frac{693 \times 11}{99} \end{aligned} = 77
3. The ratio of two numbers is 3 : 4 and their H.C.F. is 4. Their L.C.M. is
- 48
- 22
- 56
- 27
Answer: Option A
Explanation:
Let the numbers be 3x and 4x. Then, their H.C.F. = x. So, x = 4.
So, the numbers 12 and 16.
L.C.M. of 12 and 16 = 48.
4. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
- 2574
- 2500
- 1365
- 1574
Answer: Option A
Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
5. Find the HCF of 54, 288, 360
- 18
- 36
- 54
- 108
Answer: Option A
Explanation:
Lets solve this question by factorization method.
\begin{aligned}
18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5
\end{aligned}
So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}
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