Question Detail

The greatest number by which the product of three consecutive multiples of 3 is always

54
81
162
243

Answer: Option C

Explanation:

3*6*9 = 162

Similar Questions :

1. The greatest number by which the product of three consecutive multiples of 3 is always

54
81
162
243

Answer: Option C

Explanation:

3*6*9 = 162

2. 469157 * 9999

1691100843
4591100843
4691100843
3691100843

Answer: Option C

Explanation:

469157 * (10000 - 1)
= 4691570000 - 469157
= 4691100843

3. There are four prime numbers written in ascending order. The product of first three is 385 and that of last three is 1001. The last number is:

9
13
15
12

Answer: Option B

Explanation:

\begin{aligned} \frac{abc}{bcd} = \frac{385}{1001} => \frac{a}{d} = \frac{5}{13} \end{aligned}So d = 13

4. What least number should be added to 1056, so that the sum is completely divisible by 23

4
1
2
3

Answer: Option C

Explanation:

(1056 / 23) gives remainder 21

21 + 2 = 23, So we need to add 2

5. All prime numbers are odd numbers

True
False

Answer: Option B

Explanation:

It is false, 2 is an even number

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vichithra 11 years ago

3
*6
*9
which is not a lager value.but the question asked is for larger one?pls tell the reason for this answer

mastguru 11 years ago replied

Question is picked from some previous question paper.. It is considered that it is being asked from the options given.

1