The Diagonals of two squares are in the ratio of 2:5. find the ratio of their areas.

Answer: Option B

Explanation:

In this type of question, we will first calculate the distance covered in given time.
Distance covered will be, Number of revolutions * Circumference

So we will be having distance and time, from which we can calculate the speed. So let solve.

Radius of wheel = 70/2 = 35 cm
Distance covered in 40 revolutions will be

$$\begin{aligned} \text{40 * Circumference } \\ = \text{40 * 2*\pi*r } \\ = 40 * 2* \frac{22}{7}* 35 \\ = 8800 cm \\ = \frac{8800}{100} m = 88 m\\ \text{Distance covered in 1 sec =}\\ \frac{88}{10} \\ = 8.8 m \\ Speed = 8.8 m/s \\ = 8.8*\frac{18}{5} = 31.68 km/hr \end{aligned}$$

Answer: Option A

Explanation:

Clearly first we need to find the areas of the given squares, for that we need its side.

Side of sqaure = Perimeter/4

So sides are,

$$\begin{aligned} \left(\frac{24}{4}\right),\left(\frac{32}{4}\right),\left(\frac{40}{4}\right),\left(\frac{76}{4}\right),\left(\frac{80}{4}\right) \\ = 6,8,10,19,20 \\ \text{Area of new square will be }\\ = [6^2+8^2+10^2+19^2+20^2] \\ = 36+64+100+361+400 \\ = 961 cm^2 \\ \text{Side of new Sqaure =}\sqrt{961} \\ = 31 cm \\ \text{Required perimeter =}(4\times31) \\ = 124 cm \end{aligned}$$

Answer: Option D

Explanation:

As far as questions of Area or Volume and Surface area are concerned, it is all about formulas and very little logic. So its a sincere advice to get all formulas remembered before solving these questions.

Lets solve this,

$$\begin{aligned} \text{Area of rectangle =}l*b\\ \text{Area of triangle =}\frac{1}{2}l*b\\ \text{Ratio =}l*b:\frac{1}{2}l*b \\ = 1:\frac{1}{2} \\ = 2:1 \end{aligned}$$

One little thing which should be taken care in this type of question is, be sure you are calculating ration in the given order of the question.
If it is ratio of triangle and rectangle then we have to write triangle formula first. cheers :)

Answer: Option B

Explanation:

In this type of questions, first we need to calculate the area of tiles. With we can get by obtaining the length of largest tile.
Length of largest tile can be obtained from HCF of length and breadth.
So lets solve this,

Length of largest tile = HCF of (1517 cm and 902 cm)
= 41 cm

Required number of tiles =

$$\begin{aligned} \frac{\text{Area of floor}}{\text{Area of tile}} \\ = \left(\frac{1517\times902}{41 \times 41}\right)\\ = 814 \end{aligned}$$

Answer: Option A

Explanation:

$$\begin{aligned} \text{We know }h^2 = b^2+h^2 \\ =>\text{Other side }= \sqrt{(17)^2-(15)^2} \\ = \sqrt{289-225} = \sqrt{64} \\ = 8 meter \\ Area = Length \times Breadth \\ = 15\times8 m^2 = 120 m^2 \end{aligned}$$