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Question Detail
The cube root of .000216 is
- 0.6
- 0.006
- 0.06
- .0006
Answer: Option C
1. The largest four digit number which is a perfect cube, is:
- 7000
- 8000
- 9261
- 9999
Answer: Option C
Explanation:
21*21*21 = 9261
2. Evaluate \begin{aligned} \sqrt[3]{\sqrt{.000064}} \end{aligned}
- 0.0002
- 0.002
- 0.02
- 0.2
Answer: Option D
Explanation:
\begin{aligned} = \sqrt{.000064} \end{aligned}
\begin{aligned} = \sqrt{\frac{64}{10^6}} \end{aligned}
\begin{aligned} = \frac{8}{10^3} = .008 \end{aligned}
\begin{aligned} = \sqrt[3]{.008} \end{aligned}
\begin{aligned} = \sqrt[3]{\frac{8}{1000}} \end{aligned}
\begin{aligned} = \frac{2}{10} = 0.2 \end{aligned}
3. Evaluate
\begin{aligned} \sqrt[3]{4\frac{12}{125}} \end{aligned}
- \begin{aligned} 1\frac{2}{5} \end{aligned}
- \begin{aligned} 1\frac{3}{5} \end{aligned}
- \begin{aligned} 1\frac{4}{5} \end{aligned}
- 1
Answer: Option B
Explanation:
\begin{aligned}
= \sqrt[3]{\frac{512}{125}} \end{aligned}
\begin{aligned}
= (\frac{8*8*8}{5*5*5})^{\frac{1}{3}} \end{aligned}
\begin{aligned} = \frac{8}{5} = 1\frac{3}{5} \end{aligned}
4. \begin{aligned} \sqrt{\frac{32.4}{x}} = 2 \end{aligned}
- 8
- 8.1
- 9
- 9.1
Answer: Option B
5. The least perfect square, which is divisible by each of 21, 36 and 66 is
- 213414
- 213424
- 213434
- 213444
Answer: Option D
Explanation:
L.C.M. of 21, 36, 66 = 2772
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444
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