Teacher took exam for English, average for the entire class was 80 marks. If we say that 10% of the students scored 95 marks and 20% scored 90 marks then calcualte average marks of the remaining students of the class.

Answer: Option D

Answer: Option B

Explanation:

Clearly,
x% of 150 = 150 - x [as x is number of boys]

$$\begin{aligned} => x + \frac{x}{100} * 150 = 150 \\ => \frac{5}{2}x = 150 \\ => x = 60 \\ \end{aligned}$$

Answer: Option B

Explanation:

Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games,
$$\begin{aligned} = n(A\cup B) = 450-50 = 400\\ \text{Required Number}, n(A \cap B) \\ = n(A)+n(B)-n(A\cup B) \\ = 325 + 175 - 400 = 100 \end{aligned}$$

Answer: Option B

Explanation:

Let the total number is x,
then,

(100-25)% of (100 - 10)% x = 4050
=> 75% of 90% of x = 4050
=> 75/100 * 90/100 * x = 4050
=> x = (4050*50)/27 = 6000

Answer: Option A

Explanation:

Let the total number of votes enrolled are x.
Number of votes cast = 75% of x
Valid votes = 98% of 75% of x

Now, as 9261 is the 75% of valid casted votes so,

75% of 98% of 75% of x = 9261 [imporant]

$$\begin{align} => \frac{75 \times 98 \times 75 \times x}{100 \times 100 \times 100} = 9261 \\ => x = 16800 \end{align}$$