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Question Detail
Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal today
- 12
- 16
- 18
- 24
Answer: Option A
Explanation:
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
1. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
- 30
- 35
- 37
- 41
Answer: Option B
Explanation:
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
2. In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
- 35
- 37
- 39
- 41
Answer: Option C
Explanation:
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
3. The ratio between the present ages of P and Q is 6:7. If Q is 4 years old than P, what will be the ratio of the ages of P and Q after 4 years
- 7:8
- 7:9
- 3:8
- 5:8
Answer: Option A
Explanation:
Let P age and Q age is 6x years and 7x years.
Then 7x - 6x = 4 <=> x = 4
So required ratio will be (6x+4): (7x+4) => 28:32 => 7:8
4. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is
- 21 years
- 22 years
- 23 years
- 24 years
Answer: Option B
Explanation:
Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years
5. A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. How old is the mother at present
- 38
- 40
- 42
- 44
Answer: Option B
Explanation:
Let the mother's present age be x years.
Then, the person's present age = (2/5 x) years.
=> (2/5 x + 8/2) = 1 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40
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