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Question Detail
Sushil was thrice as old as Snehal 6 years back. Sushil will be times as old as Snehal 6 years hence. How old is Snehal today
- 12
- 16
- 18
- 24
Answer: Option A
Explanation:
Let Snehals age 6 years back = x.
Then, Sushils age 6 years back = 3x.
(5/3) * (X + 6 + 6) = (3X + 6 + 6)
So 5(x+ 12) = 3(3x+ 12),
so x=6.
Snehal Age = (x+ 6) years = 12 years
1. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages
- 30
- 35
- 37
- 41
Answer: Option B
Explanation:
Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.
2. Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
- 12,28
- 14,30
- 16,32
- 18,34
Answer: Option B
Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
3. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son
- 34,11
- 35,10
- 36,9
- 40,5
Answer: Option C
Explanation:
Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.
4. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
- 15 years
- 18 years
- 20 years
- 22 years
Answer: Option C
Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
5. Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 26 years. What is Deepak present age.
- 14
- 15
- 20
- 22
Answer: Option B
Explanation:
Present age is 4x and 3x,
=> 4x + 6 = 26 => x = 5
So Deepak age is = 3(5) = 15
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