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Question Detail
Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present
- 10 years
- 12 years
- 14 years
- 16 years
Answer: Option D
Explanation:
Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
\begin{aligned}
=> \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
\end{aligned}
\begin{aligned}
<=> 10(6x+10) = 11(5x+10)
\end{aligned}
\begin{aligned}
<=> 5x = 10 => x = 2
\end{aligned}
So Sagar age is (5x+6) = 16
1. The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
- 15
- 20
- 25
- 30
Answer: Option D
Explanation:
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16
(x – 6) = 3 (x-16-6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 60/2 = 30
2. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
3. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
- 20,20
- 20,10
- 25,15
- 30,10
Answer: Option D
Explanation:
Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years
4. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
- 11
- 12
- 13
- 14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
5. Ten years ago, P was half of Q in age. If the ratio of their present ages is 3:4, what will be the total of their present ages
- 35
- 34
- 45
- 25
Answer: Option A
Explanation:
Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)
=> 6x – 20 = 4x – 10
=> 2x = 10
=> x = 5
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