Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present

Answer: Option A

Explanation:

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

Answer: Option D

Explanation:

Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
$$\begin{aligned} => \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10} \end{aligned}$$
$$\begin{aligned} <=> 10(6x+10) = 11(5x+10) \end{aligned}$$
$$\begin{aligned} <=> 5x = 10 => x = 2 \end{aligned}$$

So Sagar age is (5x+6) = 16

Answer: Option C

Explanation:

Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.

Answer: Option C

Explanation:

Clue : (60 - x) - 6 = 5(x - 6)

Answer: Option B

Explanation:

Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30