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Six bells commence tolling together and toll at the intervals of 2,4,6,8,10,12 seconds resp. In 60 minutes how many times they will toll together.

  • 15
  • 16
  • 30
  • 31

Answer: Option D

Explanation:

LCM of 2-4-6-8-10-12 is 120 seconds, that is 2 minutes.

Now 60/2 = 30
Adding one bell at the starting it will 30+1 = 31

Similar Questions :

1. Find the largest number which divides 62,132,237 to leave the same reminder

  • 30
  • 32
  • 35
  • 45

Answer: Option C

Explanation:

Trick is HCF of (237-132), (132-62), (237-62)
= HCF of (70,105,175) = 35

2. What will be the LCM of 8, 24, 36 and 54

  • 54
  • 108
  • 216
  • 432

Answer: Option C

Explanation:

LCM of 8-24-36-54 will be
2*2*2*3*3*3 = 216

3. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively

  • 19
  • 17
  • 13
  • 9

Answer: Option B

Explanation:

Answer will be HCF of (400-9, 435-10, 541-14)

HCF of (391, 425, 527) = 17

4. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.

  • \begin{aligned} \frac{30}{25} \end{aligned}
  • \begin{aligned} \frac{28}{29} \end{aligned}
  • \begin{aligned} \frac{28}{29} \end{aligned}
  • \begin{aligned} \frac{16}{25} \end{aligned}

Answer: Option D

Explanation:

We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25

5. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.

  • 2574
  • 2500
  • 1365
  • 1574

Answer: Option A

Explanation:

HCF * LCM = 84942, because we know

Product of two numbers = Product of HCF and LCM

LCM = 84942/33 = 2574

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