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Question Detail
Simplify
(31/10) * (3/10) + (7/5) / 20
- 0
- 1
- 10
- 100
Answer: Option B
Explanation:
= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1
1. Simplify
\begin{aligned} 1+\frac{1}{2}+\frac{1}{4}+\frac{1}{7}+\frac{1}{14}+\frac{1}{28} = ? \end{aligned}
- 2
- 2.3
- 2.6
- 5
Answer: Option A
Explanation:
By taking LCM we get
=\begin{aligned} \frac{28+14+7+4+2+1}{28}
= \frac{56}{28} = 2\end{aligned}
2. If p - q = 3 and
\begin{aligned} p^2 + q^2 = 29 \end{aligned}, find the value of pq.
- 7
- 8
- 9
- 10
Answer: Option D
Explanation:
We know
\begin{aligned} 2ab = (a^2 + b^2) - (a - b)^2 \end{aligned}
\begin{aligned} 2pq = 29 - 9 = 20 \end{aligned}
\begin{aligned} =>pq = 10 \end{aligned}
3. Simplify
\begin{aligned} 1\frac{3}{4}+5\frac{1}{3}+3\frac{2}{5} \end{aligned}
- \begin{aligned}10\frac{29}{60} \end{aligned}
- \begin{aligned}8\frac{29}{60} \end{aligned}
- \begin{aligned}6\frac{29}{60} \end{aligned}
- \begin{aligned}4\frac{29}{60} \end{aligned}
Answer: Option A
Explanation:
\begin{aligned} = \frac{7}{4}+\frac{16}{3}+\frac{17}{5} \end{aligned}
\begin{aligned} = \frac{105+320+204}{60}
\end{aligned}
\begin{aligned} = \frac{629}{60}
\end{aligned}
\begin{aligned} = 10\frac{29}{60}
\end{aligned}
4. If a - b = 3 and \begin{aligned} a^2 + b^2 = 29 \end{aligned}, then find the value of ab
- 7
- 8.5
- 10
- 12
Answer: Option C
Explanation:
Remember the formula, if not then cram it :)
\begin{aligned} 2ab = (a^2 + b^2)- (a-b)^2 \end{aligned}
=> 2ab = 29 - 9 = 20
=> ab = 10
5. \begin{aligned} 3034 -(1002 \div 20.04) = ? \end{aligned}
- 1964
- 1984
- 2964
- 2984
Answer: Option D
Explanation:
\begin{aligned}
= 3034 -( \frac{1002}{2004} \times 100)
\end{aligned}
\begin{aligned}
= 3034 - 50 = 2984
\end{aligned}
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