Question Detail
Shweta goes towards East 5 km then she takes a turn to South-West and goes 5 km. She again takes a turn towards North-West and goes 5 km with respect to the point from where she started, where is she now ?
- In the South-West
- In the North-West
- In the East
- At the starting Point
Answer: Option D
1. Rohit walked 25 metres towards South. Then he turned to his left and walked 20 metres. He then turned to his left and walked 25 metres. He again turned to his right and walked 15 metres. At what distance is he from the starting point and in which direction ?
- 35 metre, North
- 30 metre, South
- 35 metre, East
- 30 metre, North
Answer: Option C
Explanation:
The movements of Rohit are shown in figure.
Rohit's distance from the starting point A will be
AE = AD+DE = 20 + 15 = 35 metre
And direction with reference to the starting point is east.
2. Starting from a point P, Sachin walked 20 metres towards South. He turned left and walked 30 metres. He then turned left and walked 20 metres. He again turned left and walked 40 metres and reached a point Q. How far and in which direction is the point Q from the point P ?
- 30 metres, West
- 10 metres, West
- 30 metres, North
- 10 metres, North
Answer: Option B
Explanation:
Please refer to the image for movements.
Distance from the P to Q is 10 metres and direction of Q with reference to to P is west.
3. A child is looking for his father. He went 90 meters in the east before turning to his right. He went 20 meters before turning to is right again to look for his father at his uncle's place 30 meters from this point. His father was not there. From there, he went 100 meters to his north before meeting his father in a street. How far did the son meet his father from starting point ?
- 80 metre
- 90 metre
- 100 metre
- 110 metre
Answer: Option C
Explanation:
Clearly, the child moves from A to B 90 metres eastwards upto B, then turns right and moves 20 metre upto C, then turns right and moves upto 30 metre upto D. Finally he turns right and moves upto 100 metre upto E.
So AB = 90 metre, BF = CD = 30 metre,
So, AF = AB - BF = 60 metre
Also DE = 100 metre, DF = BC = 20 metre
So, EF = DE - DF = 80 metre
as we can see in image that triangle AFE is a right angled triangle and we are having two sides, need to calculate third one, so we can apply Pythagoras theorem here
\begin{aligned}
A = AE = \sqrt{AF^2 + EF^2} \\
= \sqrt{(60)^2+(80)^2} \\
= \sqrt{3600+6400} \\
= \sqrt{10000} = 100
\end{aligned}
So from starting point his father was 100 metre away.
4. A man is facing west. He turns 45 degree in the clockwise direction and then another 180 degree in the same direction and then 270 degree in the anticlockwise direction. Find which direction he is facing now ?
- South-West
- West
- South
- East-South
Answer: Option A
Explanation:
Please refer to the explanation image.
The man firstly faces the direction OA. On moving 45 degree clockwise[Please check carefully always if clockwise or anticlockwise], he faces the direction OB.
Now again he moved 180 degree clockwise, now he will be facing OC. From here he moved 270 degree anticlockwise, Finally he is facing OD, which is South west.
5. Shweta goes towards East 5 km then she takes a turn to South-West and goes 5 km. She again takes a turn towards North-West and goes 5 km with respect to the point from where she started, where is she now ?
- In the South-West
- In the North-West
- In the East
- At the starting Point
Answer: Option D