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Question Detail
Sahil took a loan for 6 years at the rate of 5% per annum on Simple Interest, If the total interest paid was Rs. 1230, the principal was
- 4100
- 4200
- 4300
- 4400
Answer: Option A
Explanation:
\begin{aligned}
\text{S.I.} = \frac{P*R*T}{100} \\
=> P = \frac{S.I. * 100}{R*T}
\end{aligned}
By applying above formula we can easily solve this question, as we are already having the simple interest.
\begin{aligned}
=> P = \frac{1230 * 100}{6*5} \\
=> P = 4100
\end{aligned}
1. If A lends Rs. 3500 to B at 10% p.a. and B lends the same sum to C at 11.5% p.a., then the gain of B (in Rs.) in a period of 3 years is
- Rs. 154.50
- Rs. 155.50
- Rs. 156.50
- Rs. 157.50
Answer: Option D
Explanation:
We need to calculate the profit of B.
It will be,
SI on the rate B lends - SI on the rate B gets
\begin{aligned}
\text{Gain of B}\\ &= \frac{3500\times11.5\times3}{100} - \frac{3500\times10\times3}{100}\\
= 157.50
\end{aligned}
2. At 5% per annum simple interest, Rahul borrowed Rs. 500. What amount will he pay to clear the debt after 4 years
- 750
- 700
- 650
- 600
Answer: Option D
Explanation:
We need to calculate the total amount to be paid by him after 4 years, So it will be Principal + simple interest.
So,
\begin{aligned}
=> 500 + \frac{500*5*4}{100}
=> Rs. 600
\end{aligned}
3. At what rate percent per annum will the simple interest on a sum of money be 2/5 of the amount in 10 years
- 1%
- 2%
- 3%
- 4%
Answer: Option D
Explanation:
Let sum = x
Time = 10 years.
S.I = 2x /5, [as per question]
Rate =( (100 * 2x) / (x*5*10))%
=> Rate = 4%
4. What will the ratio of simple interest earned by certain amount at the same rate of interest for 6 years and that for 9 years.
- 1:2
- 2:1
- 2:2
- 2:3
Answer: Option D
Explanation:
Let the principal be P and rate be R
then
\begin{aligned}
\text{ratio = } [\frac{(\frac{P*R*6}{100})}{(\frac{P*R*9}{100})}] \\
= \frac{6PR}{9PR} = 2:3
\end{aligned}
5. Find the simple interest on Rs 7000 at 50/3 % for 9 months
- Rs. 1075
- Rs. 975
- Rs. 875
- Rs. 775
Answer: Option C
Explanation:
\begin{aligned}
\text{ S.I. = } \frac{P \times R \times T}{100}
\end{aligned}
So, by putting the values in the above formula, our result will be.
\begin{aligned}
\text{ Required result = } \frac{7000 \times 50 \times 9}{3 \times 12 \times 100} = 875
\end{aligned}
[Please note that we have divided by 12 as we converted 9 months in a year format]
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