Sahil purchased a machine at Rs 10000, then got it repaired at Rs 5000, then gave its transportation charges Rs 1000. Then he sold it with 50% of profit. At what price he actually sold it.

Answer: Option B

Explanation:

Let the cost of Production = Rs. P
Then, as per question,

\begin{aligned}
=> \left( \frac{125}{100} *\frac{115}{100}*\frac{110}{100} * P \right) = 1265\\
=> \frac{253}{160}P = 1265 \\
=> P = 800
\end{aligned}

Answer: Option C

Explanation:

Let the S.P = 100
then C.P. = 25

Profit = 75

Profit% = 75/25 * 100 = 3005

Answer: Option B

Explanation:

Let the Cost Price of 1 item = Re. 1
Cost Price of 16 items = 16
Selling Price of 16 items = 12

Loss = 16 - 12 = Rs 4

Loss % = (4/16)* 100 = 25%

Answer: Option D

Explanation:

Let the Cost Price of one article = Rs. 1
CP of x articles = Rs. x
CP of 20 articles = 20
Selling price of x articles = 20

Profit = 25% [Given]

\begin{aligned}
\Rightarrow \left (\dfrac{SP - CP }{CP}\right ) = \dfrac{25}{100} = \dfrac{1}{4}

& \Rightarrow \dfrac{\left(20-x \right )}{x} = \dfrac{1}{4} \\
& \Rightarrow 80 - 4x = x \\
& \Rightarrow 5x = 80 \nonumber \\
& \Rightarrow x = \dfrac{80}{5} = 16 \\

\end{aligned}

Answer: Option C

Explanation:

We need to get the Total selling price to solve this question. Because after getting selling price we can get profit or loss, then we can calculate profit% or loss%

So lets solve this:

Price Received by selling one fourth of the material at a loss of 20% =
(1/4) * 600 * (80/100) = Rs. 120

Price Received by remaining material at a gain of 10% =
(3/4) * 600 * (110/100) = Rs. 495 [Note: 1-(1/4) = 3/4]

Total Selling Price = 120 + 465 = Rs. 615

Profit = 615 - 600 = 15

\begin{aligned}
Profit\% = \left( \frac{Gain}{Cost} * 100 \right)\% \\
= \left( \frac{15}{600} * 100 \right)\% \\
= \frac{5}{2}\% = 2\frac{1}{2}\%
\end{aligned}