Question Detail

Sachin was twice as old as Ajay 10 years back. How old is Ajay today if Sachin will be 40 years old 10 years hence

Answer: Option D

Explanation:

Sachin's age today = 30 years.
Sachin's age 10 years back = 20 years.
Ajay's age 10 years back = 10 years.
Ajay's age today =20 years

1. Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages

Answer: Option B

Explanation:

Let A's age 10 years ago = x years.
Then, B's age 10 years ago = 2x years.
(x + 10) / (2x+ lO) = 3/4
=> x = 5.
So, the total of their present ages =(x + 10 + 2x + 10)
= (3x + 20) = 35 years.

2. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is

21 years
22 years
23 years
24 years

Answer: Option B

Explanation:

Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years

3. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is

90
98
120
Data is not adequate

Answer: Option D

4. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju

Answer: Option C

Explanation:

Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10

5. Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin

23.5
24.5
12.5
14.5

Answer: Option B

Explanation:

If Rahul age is x, then Sachin age is x-7,
so (x-7)/x = 7/9
=> 9x-63 = 7x
=> 2x = 63
=> x = 31.5

So Sachin age is 31.5 - 7 = 24.5