Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Sachin

Answer: Option C

Explanation:

Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years

Answer: Option B

Explanation:

Let's Son age is x, then Father age is x+24.
=> 2(x+2) = (x+24+2)
=> 2x+4 = x+26
=> x = 22 years

Answer: Option B

Explanation:

Let the mother's present age be x years.
Then, the person's present age = (2/5 x) years.

=> (2/5 x + 8/2) = 1 (x + 8)
=> 2(2x + 40) = 5(x + 8)
=> x = 40

Answer: Option A

Explanation:

Let the present age of P and Q be 3x and 4x respectively.
Ten years ago, P was half of Q in age
=> 2(3x – 10) = (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

Answer: Option D

Explanation:

Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
then,
$$\begin{aligned} => \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10} \end{aligned}$$
$$\begin{aligned} <=> 10(6x+10) = 11(5x+10) \end{aligned}$$
$$\begin{aligned} <=> 5x = 10 => x = 2 \end{aligned}$$

So Sagar age is (5x+6) = 16