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Question Detail
Rs. 120 are divided among A, B, C such that A's share is Rs. 20 more than B's and Rs. 20 less than C's. What is B's share
- Rs 10
- Rs 20
- Rs 24
- Rs 28
Answer: Option B
Explanation:
Let C = x. Then A = (x—20) and B = (x—40).
x + x - 20 + x - 40 = 120 Or x=60.
A:B:C = 40:20:60 = 2:1 :3.
B's share = Rs. 120*(1/6) = Rs. 20
1. if x:y = 1:3, then find the value of
(7x+3y):(2x+y)
- 14:5
- 15:5
- 16:5
- 17:5
Answer: Option C
Explanation:
let x = 1k and y = 3k, so
\begin{aligned}
= \frac{7(k)+3(3k)}{2(k)+1(3k)} \\
= \frac{16k}{5k} \\
= 16:5
\end{aligned}
2. If 2 : 9 :: x : 18, then find the value of x
- 2
- 3
- 4
- 6
Answer: Option C
Explanation:
Treat 2:9 as 2/9 and x:18 as x/18, treat :: as =
So we get 2/9 = x/18
=> 9x = 36
=> x = 4
3. In a college, the ratio of the number of boys to girls is 8 : 5. If there are 200 girls, the total number of students in the college is
- 420
- 520
- 620
- 720
Answer: Option B
Explanation:
Let the boy are 8x and Girls are 5x
=> 5x = 200
=> x = 40
Total students = 8x+5x = 13x = 13(40) = 520
4. The salaries of A, B and C are of ratio 2:3:5. If the increments of 15%, 10% and 20% are done to their respective salaries, then find the new ratio of their salaries.
- 20:33:60
- 21:33:60
- 22:33:60
- 23:33:60
Answer: Option D
Explanation:
Let A salary be 2k
B salary be 3k and C salary be 5k
\begin{aligned}
\text{A's new salary = }\frac{115}{100}*2k \\
= \frac{23}{10}k \\
\text{B's new salary = }\frac{110}{100}*3k \\
= \frac{33}{10}k \\
\text{C's new salary = }\frac{120}{100}*5k \\
= 6k \\
\text{New ratio = }\\
\frac{23k}{10}:\frac{33k}{10}:6k \\
= 23:33:60 \\
\end{aligned}
5. If a:b = 2:3 and b:c = 4:3, then find a:b:c
- 8:12:9
- 2:3:8
- 2:3:9
- 2:3:12
Answer: Option A
Explanation:
\begin{aligned}
a:b = 2:3 \\
b:c = 4:3 = (4*\frac{3}{4} : 3*\frac{3}{4}) \\
= 3:\frac{9}{4} \\
a:b:c = 2:3:\frac{9}{4} \\
= 8:12:9
\end{aligned}
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