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Reena is twice as old as Sunita. Three years ago, she was three times as old as Sunita. How old is Reena now ?

  • 6 years
  • 12 years
  • 14 years
  • 16 years

Answer: Option B

Explanation:

Let Sunita's present age = x years
Then Reena present age = 2x years

Three years ago
(2x-3) = 3(x-3)
2x - 3 = 3x - 9
or x = 6

Reena age = 2x = 2*6 = 12 year.

Similar Questions :

1. A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?

  • 12
  • 16
  • 24
  • 18

Answer: Option B

Explanation:

Suppose boy got x sums right and 2x sums wrong,
then,
x+2x = 48
=> 3x = 48
=> x = 16

2. A shepherd had 27 sheep. All but 10 died. How many he left with ?

  • 10
  • 15
  • 17
  • 27

Answer: Option A

Explanation:

"All but 10 died" means all except 10 died, so he is remained with 10 sheep.

3. A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

  • 9, 46
  • 9, 50
  • 10, 46
  • 10, 50

Answer: Option B

Explanation:

As from the question we have,
A = 3B --- (i)
c - 4 = 2(A+4) ---(ii)

Also, A + 4 = 31
or A = 31-4 = 27

Putting A = 27 in (i) we get
B = 9
Putting A = 27 in (ii) we get
C = 50

4. At the end of a business conference the ten people present all shake hands with each other once. How many handshakes will there be altogether ?

  • 20
  • 45
  • 55
  • 90

Answer: Option B

Explanation:

Total number of handshakes =
9+8+7+6+5+4+3+2+1 = 45

5. First bunch of bananas has (1/4) again as many bananas as a second bunch. If the second bunch has 3 bananas less than the first bunch, then the number of bananas in the first bunch are

  • 9
  • 10
  • 12
  • 15

Answer: Option D

Explanation:

Let the number of bananas in the second bunch be x.
Then, the number of bananas in the first bunch
= x + 1/4 x
= 5/4 x
So,
5/4 x - x = 3
=> 5x - 4x = 12
x = 12

Number of bananas in first bunch
= 5/4 * 12 = 15

Read more from - Arithmetic Reasoning Questions Answers
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