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Question Detail
Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.
- \begin{aligned} \frac{30}{25} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{16}{25} \end{aligned}
Answer: Option D
Explanation:
We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25
1. Find the greatest number that will divide 400, 435 and 541 leaving 9, 10 and 14 as remainders respectively
- 19
- 17
- 13
- 9
Answer: Option B
Explanation:
Answer will be HCF of (400-9, 435-10, 541-14)
HCF of (391, 425, 527) = 17
2. The H.C.F. and L.C.M. of two numbers are 12 and 5040 respectively If one of the numbers is 144, find the other number
- 400
- 256
- 120
- 420
Answer: Option D
Explanation:
Solve this question by using below formula.
Product of 2 numbers = product of their HCF and LCM
144 * x = 12 * 5040
x = (12*5040)/144 = 420
3. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.
- \begin{aligned} \frac{30}{25} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{16}{25} \end{aligned}
Answer: Option D
Explanation:
We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25
4. Find the HCF of 2.1, 1.05 and 0.63
- 0.44
- 0.64
- 0.21
- None of above
Answer: Option C
Explanation:
To solve this question quickly, first remove decimal by multiplying each term with 100,
Then terms become 210, 105, 63
Then HCF of above terms is 21,
So Answer is 0.21
5. Find the HCF of \begin{aligned} \frac{2}{3}, \frac{4}{6}, \frac{8}{27} \end{aligned}
- \begin{aligned} \frac{2}{27} \end{aligned}
- \begin{aligned} \frac{8}{3} \end{aligned}
- \begin{aligned} \frac{2}{3} \end{aligned}
- \begin{aligned} \frac{8}{27} \end{aligned}
Answer: Option A
Explanation:
Whenever we have to solve this sort of question, remember the formula.
HCF = \begin{aligned} \frac{HCF of Numerators}{LCM of Denominators} \end{aligned}
So answers will be option 1
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