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Question Detail
Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.
- 16,35,36
- 12,28,36
- 16,28,27
- 16,28,36
Answer: Option D
Explanation:
Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4
So their present ages are: 16,28,36
1. Raju age after 15 years will be 5 times his age 5 years back, What is the present age of Raju
- 15
- 14
- 10
- 8
Answer: Option C
Explanation:
Clearly,
x+15 = 5(x-5)
<=> 4x = 40 => x = 10
2. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is
- 90
- 98
- 120
- Data is not adequate
Answer: Option D
3. Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
- 12,28
- 14,30
- 16,32
- 18,34
Answer: Option B
Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
4. In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
- 35
- 37
- 39
- 41
Answer: Option C
Explanation:
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
5. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the fathers age at that time. The present age of father and son
- 34,11
- 35,10
- 36,9
- 40,5
Answer: Option C
Explanation:
Let sons age = x years. Then fathers age = (45 - x)years.
(x—5)(45—x—5) = 4(45- x - 5) hence (x—5) = 4 so x = 9
Their ages are 36 years and 9 years.
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