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Question Detail
Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.
- 16,35,36
- 12,28,36
- 16,28,27
- 16,28,36
Answer: Option D
Explanation:
Let the present ages are 4x, 7x, 9x.
=> (4x-8) + (7x-8) + (9x-8) = 56
=> 20x = 80
=> x = 4
So their present ages are: 16,28,36
1. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be
- 15 years
- 18 years
- 20 years
- 22 years
Answer: Option C
Explanation:
Clue : (60 - x) - 6 = 5(x - 6)
2. In 10 years, A will be twice as old5as B was 10 years ago. If A is now 9 years older than B, the present age of B is
- 35
- 37
- 39
- 41
Answer: Option C
Explanation:
Let B's age = x years.
Then, As age = (x+ 9) years.
(x+9+10)=2(x—10)
hence x=39.
Present age of B = 39 years
3. The ages of two persons differ by 20 years. If 5 years ago, the elder one be 5 times as old as the younger one, their present ages (in years) are respectively
- 20,20
- 20,10
- 25,15
- 30,10
Answer: Option D
Explanation:
Let their ages be x and (x + 20) years.
5 (x - 5) = (x + 20 - 5) or 4x = 40 or x = 10.
Their present ages are 30 years and 10 years
4. The total age of A and B is 12 years more than the total age of B and C. C is how many year younger than A
- 11
- 12
- 13
- 14
Answer: Option B
Explanation:
Given that A+B = 12 + B + C
=> A – C = 12 + B – B = 12
=> C is younger than A by 12 years
5. Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age
- 12,28
- 14,30
- 16,32
- 18,34
Answer: Option B
Explanation:
Let the age of younger person is x,
Then elder person age is (x+16)
=> 3(x-6) = (x+16-6) [6 years before]
=> 3x-18 = x+10
=> x = 14.
So other person age is x + 16 = 30
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