Raman's salary was decreased by 50% and subsequently increased by 50%. How much percent does he loss.

Answer: Option B

Explanation:

Number of runs made by running = 110 - (3 x 4 + 8 x 6)
= 120 - (60)
= 60

Now, we need to calculate 60 is what percent of 120.

=> 60/120 * 100 = 50 %

Answer: Option A

Explanation:

1/2/1/3 * 100 = 1/2 * 3/1 * 100 = 150 %

Answer: Option D

Explanation:

$$\begin{aligned} n(A) = \left(\frac{60}{100}*96\right) = \frac{288}{5} \\ n(B) = \left(\frac{30}{100}*96\right) = \frac{144}{5} \\ n(A\cap B) = \left(\frac{15}{100}*96\right) = \frac{72}{5} \\ \text{People who have either or both lunch} \\ n(A\cup B) = \frac{288}{5}+\frac{144}{5}-\frac{72}{5} \\ = \frac{360}{5} = 72 \end{aligned}$$

So People who do no have either lunch were = 96 -72
= 24

Answer: Option A

Explanation:

Let the original price per egg be Rs x
Then increased price will be,
$$\begin{aligned} \left(\frac{130}{100}x\right) \\ => \frac{7.80}{x}-\frac{7.80}{\frac{130}{100}x} = 3\\ => \frac{7.80}{x}-\frac{780}{130x} = 3 \\ => 390x = 234 \\ => x = 0.6 \\ \text{Actual price was Rs 0.6} \\ \text{Present price per dozen will be} \\ Rs.\left(12*\frac{130}{100}*0.6 \right) \\ = Rs. 9.36 \end{aligned}$$

Answer: Option A

Explanation:

Let the number be x,
then,
$$\begin{aligned} \frac{5}{3} - \frac{3}{5} = \frac{16}{15}x \end{aligned}$$

Error% = $$\begin{aligned} (\frac{16}{15}x * \frac{3}{5} * 100)% = 64% \end{aligned}$$