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Problems on Ages Questions Answers

  • 15. Six years ago, the ratio of the ages of Kunal and Sagar was 6:5, Four years hence, the ratio of their ages will be 11:10. What is Sagar age at present

    1. 10 years
    2. 12 years
    3. 14 years
    4. 16 years
    Answer And Explanation

    Answer: Option D

    Explanation:

    Let six years ago the age of Kunal and Sagar are 6x and 5x resp.
    then,
    \begin{aligned}
    => \frac{(6x+6)+4}{(5x+6)+4} = \frac{11}{10}
    \end{aligned}
    \begin{aligned}
    <=> 10(6x+10) = 11(5x+10)
    \end{aligned}
    \begin{aligned}
    <=> 5x = 10 => x = 2
    \end{aligned}

    So Sagar age is (5x+6) = 16

  • 16. Average age of A and B is 24 years and average age of B, C and D is 22 years. The sum of the ages of A, B, C and D is

    1. 90
    2. 98
    3. 120
    4. Data is not adequate
    Answer And Explanation

    Answer: Option D

  • 17. Total of the ages of A, B ahd C at present is 90 years. Ten years ago, the ratio of their ages was 1: 2: 3. What is the age of B at present

    1. 25
    2. 30
    3. 45
    4. 60
    Answer And Explanation

    Answer: Option B

    Explanation:

    Let their ages 10 years ago is x, 2x and 3x years.
    10 + 2x + 10 + 3x + 10 = 90 hence x= 10
    B’s present age = (2x + 10) =30 years

  • 18. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is

    1. 20 years
    2. 21 years
    3. 22 years
    4. 24 years
    Answer And Explanation

    Answer: Option C

    Explanation:

    Let the son's present age be x years. Then, man's present age = (x + 24) years
    => (x + 24) + 2 = 2(x + 2)
    => x + 26 = 2x + 4
    So, x = 22

  • 19. Ratio of ages of three persons is 4:7:9, Eight years ago, the sum of their ages was 56. Find their present ages.

    1. 16,35,36
    2. 12,28,36
    3. 16,28,27
    4. 16,28,36
    Answer And Explanation

    Answer: Option D

    Explanation:

    Let the present ages are 4x, 7x, 9x.
    => (4x-8) + (7x-8) + (9x-8) = 56
    => 20x = 80
    => x = 4

    So their present ages are: 16,28,36

  • 20. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is

    1. 21 years
    2. 22 years
    3. 23 years
    4. 24 years
    Answer And Explanation

    Answer: Option B

    Explanation:

    Let's Son age is x, then Father age is x+24.
    => 2(x+2) = (x+24+2)
    => 2x+4 = x+26
    => x = 22 years

  • 21. Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. What was ratio of ages of Tanya and her grandfather 8 years ago.

    1. 11:50
    2. 11:51
    3. 11:53
    4. 11:54
    Answer And Explanation

    Answer: Option C

    Explanation:

    Let, Tanya age 16 years ago = x,
    Grandfather's age 16 years ago = 8x.

    8 years from now, 3(x+16+8) = (8x+16+8)
    => x = 48/5

    8 years ago ratio was:

    \begin{aligned}
    => \frac{x+8}{8x+8} = \frac{\frac{48}{5}+8}{8 \times \frac{48}{5}+8}
    \end{aligned}

    \begin{aligned}
    => \frac{88}{424} = \frac{11}{53}
    \end{aligned}