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Probability Questions Answers

  • 1. In a throw of coin what is the probability of getting head.

    1. 1
    2. 2
    3. 1/2
    4. 0
    Answer And Explanation

    Answer: Option C

    Explanation:

    Total cases = [H,T] - 2
    Favourable cases = [H] -1
    So probability of getting head = 1/2

  • 2. In a throw of coin what is the probability of getting tails.

    1. 1
    2. 2
    3. 1/2
    4. 0
    Answer And Explanation

    Answer: Option C

    Explanation:

    Total cases = [H,T] - 2
    Favourable cases = [T] -1
    So probability of getting tails = 1/2

  • 3. Two unbiased coins are tossed. What is probability of getting at most one tail ?

    1. \begin{aligned} \frac{1}{2} \end{aligned}
    2. \begin{aligned} \frac{1}{3} \end{aligned}
    3. \begin{aligned} \frac{3}{2} \end{aligned}
    4. \begin{aligned} \frac{3}{4} \end{aligned}
    Answer And Explanation

    Answer: Option D

    Explanation:

    Total 4 cases = [HH, TT, TH, HT]
    Favourable cases = [HH, TH, HT]
    Please note we need atmost one tail, not atleast one tail.

    So probability = 3/4

  • 4. Three unbiased coins are tossed, what is the probability of getting at least 2 tails ?

    1. 1/3
    2. 1/6
    3. 1/2
    4. 1/8
    Answer And Explanation

    Answer: Option C

    Explanation:

    Total cases are = 2*2*2 = 8, which are as follows
    [TTT, HHH, TTH, THT, HTT, THH, HTH, HHT]

    Favoured cases are = [TTH, THT, HTT, TTT] = 4

    So required probability = 4/8 = 1/2

  • 5. In a throw of dice what is the probability of getting number greater than 5

    1. 1/2
    2. 1/3
    3. 1/5
    4. 1/6
    Answer And Explanation

    Answer: Option D

    Explanation:

    Number greater than 5 is 6, so only 1 number
    Total cases of dice = [1,2,3,4,5,6]

    So probability = 1/6

  • 6. What is the probability of getting a sum 9 from two throws of dice.

    1. 1/3
    2. 1/9
    3. 1/12
    4. 2/9
    Answer And Explanation

    Answer: Option B

    Explanation:

    Total number of cases = 6*6 = 36

    Favoured cases = [(3,6), (4,5), (6,3), (5,4)] = 4

    So probability = 4/36 = 1/9

  • 7. Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even ?

    1. 3/4
    2. 1/4
    3. 7/4
    4. 1/2
    Answer And Explanation

    Answer: Option A

    Explanation:

    Total number of cases = 6*6 = 36

    Favourable cases = [(1,2),(1,4),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,2),(3,4),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,2),(5,4),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)] = 27

    So Probability = 27/36 = 3/4