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Question Detail
On a sum of money, simple interest for 2 years is Rs 660 and compound interest is Rs 696.30, the rate of interest being the same in both cases.
- 8%
- 9%
- 10%
- 11%
Answer: Option D
Explanation:
Difference between C.I and S.I for 2 years = 36.30
S.I. for one year = 330.
S.I. on Rs 330 for one year = 36.30
So R% = \frac{100*36.30}{330*1} = 11%
1. At what rate of compound interest per annum will a sum of Rs. 1200 become Rs. 1348.32 in 2 years
- 3%
- 4%
- 5%
- 6%
Answer: Option D
Explanation:
Let Rate will be R%
1200(1+R100)2=134832100(1+R100)2=134832120000(1+R100)2=1123610000(1+R100)=106100=>R=6%
2. We need to divide Total Sum Rs. 3364 between Ram and Sham so that Ram's share at the end of 5 years may equal to Sham's share at the end of seven years with compound interest rate at 5 percent.
- 1864 and 1500
- 1764 and 1600
- 1664 and 1700
- 1564 and 1800
Answer: Option B
Explanation:
It is clear from question that Ram's share after five years = Sham's share after seven years
Hence we can conclude following :
(Rams's present share)(1+5100)5=(Sham's present share)(1+5100)7=>(Ram's present share)(Sham's present share)=(1+5100)7(1+5100)5=(1+5100)(7−5)=(1+5100)2=(2120)2=441400
Ram's present share : B's present share = 441 : 400
As amount is Rs.3364, Ram's share = 3364×441(441+400)=3364×441841=4×441= Rs. 1764
So Sham's share is = 3364-1764 = 1600
3. The difference between simple and compound interests compounded annually on a certain sum of money for 2 years at 4% per annum is Rs 1. Find the sum
- Rs 600
- Rs 625
- Rs 650
- Rs 675
Answer: Option B
Explanation:
Let the Sum be P
S.I.=P∗4∗2100=2P25C.I.=P(1+4100)2−P=676P625−P=51P625As, C.I. - S.I = 1=>51P625−2P25=1=>51P−50P625=1P=625
4. Find the compound interest on Rs. 7500 at 4% per annum for 2 years, compounded annually.
- Rs. 610
- Rs. 612
- Rs. 614
- Rs. 616
Answer: Option B
Explanation:
Amount=[7500×(1+4100)2]=(7500×2625×2625)=8112
So compound interest = (8112 - 7500) = 612
5. A man saves Rs 200 at the end of each year and lends the money at 5% compound interest. How much will it become at the end of 3 years.
- Rs 662
- Rs 662.01
- Rs 662.02
- Rs 662.03
Answer: Option C
Explanation:
=[200(2120×2120×2120)+200(2120×2120)+200(2120)]=662.02
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