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Question Detail
LCM of two numbers is 7700 and HCF is 11. If one number is 308 then other number is
- 269
- 285
- 300
- 275
Answer: Option D
1. Reduce \begin{aligned}
\frac{368}{575}
\end{aligned} to the lowest terms.
- \begin{aligned} \frac{30}{25} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{28}{29} \end{aligned}
- \begin{aligned} \frac{16}{25} \end{aligned}
Answer: Option D
Explanation:
We can do it easily by in two steps
Step1: We get the HCF of 368 and 575 which is 23
Step2: Divide both by 23, we will get the answer 16/25
2. Find the HCF of 54, 288, 360
- 18
- 36
- 54
- 108
Answer: Option A
Explanation:
Lets solve this question by factorization method.
\begin{aligned}
18 = 2 \times 3^2, 288 = 2^5 \times 3^2, 360 = 2^3 \times 3^2 \times 5
\end{aligned}
So HCF will be minimum term present in all three, i.e.
\begin{aligned}
2 \times 3^2 = 18
\end{aligned}
3. Find the greatest number which on dividing 1661 and 2045, leaves a reminder of 10 and 13 respectively
- 125
- 127
- 129
- 131
Answer: Option B
Explanation:
In this type of question, its obvious we need to calculate the HCF, trick is
HCF of (1661 - 10) and (2045 -13)
= HCF (1651, 2032) = 127
4. Find the HCF of
\begin{aligned}
2^2 \times 3^2 \times 7^2, 2 \times 3^4 \times 7
\end{aligned}
- 128
- 126
- 146
- 434
Answer: Option B
Explanation:
HCF is Highest common factor, so we need to get the common highest factors among given values. So we got
2 * 3*3 * 7
5. If the product of two numbers is 84942 and their H.C.F. is 33, find their L.C.M.
- 2574
- 2500
- 1365
- 1574
Answer: Option A
Explanation:
HCF * LCM = 84942, because we know
Product of two numbers = Product of HCF and LCM
LCM = 84942/33 = 2574
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