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Question Detail
In the series 3, 9, 15.. what will be the 21st term ?
- 123
- 126
- 129
- 136
Answer: Option A
Explanation:
We can judge that it is A.P.
With 6 as difference
nth term in A.P. = a+(n-1)d
a= 3, n = 21, d = 6
So, 21st term will be = 3+(20)6 = 123
1. 1, 2, 5, 12, 27, 58, 121, ?
- 248
- 244
- 198
- 190
Answer: Option A
Explanation:
Pattern in the series is *2+1, *2+2, *2+3,.....
Term which replaces the question mark in the series is
121 * 2 + 6 = 248
2. Complete the series 2,2,5, 13,28,....
- 50
- 51
- 52
- 53
Answer: Option C
Explanation:
\begin{aligned}
\text{Pattern is }\\
+1^2-1, +2^2-1, +3^2-1,+4^2-1 \\
5^2-1 = 28 + 24 \\
= 52
\end{aligned}
3. Which fraction will come next, \begin{aligned} \frac{1}{2}, \frac{3}{4}, \frac{5}{8}, \frac{7}{16}, ? \end{aligned}
- \begin{aligned} \frac{11}{32} \end{aligned}
- \begin{aligned} \frac{9}{28} \end{aligned}
- \begin{aligned} \frac{9}{30} \end{aligned}
- \begin{aligned} \frac{9}{32} \end{aligned}
Answer: Option D
Explanation:
Numerators of the fractions in the given sequence are getting increased by 2, i.e. 1+2,3+2,5+2, so next will be 7+2 = 9
Denominators of the fractions in the series is getting doubled, 2*2 = 4, 4*2 = 8, 8*2 = 16, no next will be 16*2 = 32
So resulting fraction will be
\begin{aligned}
\frac{9}{32}
\end{aligned}
4. 1,6,15,(...),45,66,91
- 26
- 28
- 29
- 34
Answer: Option B
Explanation:
Pattern in the series is, +5, +9, .., .., +21, +25
So 4 is getting increased at every term addition.
Missing term in the series will be 15+(9+4)
= 15+13 = 28
5. 8, 9, 8, 7, 10, 9, 6, 11, 10, (...), 12
- 7
- 6
- 5
- 4
Answer: Option C
Explanation:
Please note that above sequence is containing 3 series
Series 1 : 8, 7, 6, (..)
Series 2 : 9, 10, 11, 12
Series 3 : 8, 9, 10
In series 1 pattern is -1. So missing term will be 6-1 = 5
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