Question Detail
In a hotel, 60% had vegetarian lunch while 30% had non-vegetarian lunch and 15% had both type of lunch. If 96 people were present, how many did not eat either type of lunch ?
- 27
- 26
- 25
- 24
Answer: Option D
Explanation:
n(A)=(60100∗96)=2885n(B)=(30100∗96)=1445n(A∩B)=(15100∗96)=725People who have either or both lunchn(A∪B)=2885+1445−725=3605=72
So People who do no have either lunch were = 96 -72
= 24