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Question Detail
In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?
- 3 hours
- 2.4 hours
- 1.4 hours
- 1 hour
Answer: Option D
Explanation:
Let the duration of the flight be x hours.
Then
\begin{aligned}
\frac{600}{x}-\frac{600}{x + \frac{1}{2}} = 200 \\
\frac{600}{x}-\frac{1200}{2x+1} = 200 \\
x(2x+1) = 3 \\
2x^2 + x - 3 = 0 \\
=> (2x+3)(x-1)=0
\end{aligned}
Neglecting the negative value for x we get x = 1
1. The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
- 10 am
- 11 am
- 12 pm
- 1 pm
Answer: Option B
Explanation:
Suppose they meet x hrs after 8 a.m.
then
(Distance moved by first in x hrs) + [Distance moved by second in (x-1) hrs]
= 330
So, 60x+75(x-1) = 330
x=3.
So,they meet at (8+3). i.e 11a.m.
2. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour ?
- 8 minutes
- 10 mintues
- 12 minutes
- 14 minutes
Answer: Option B
Explanation:
Due to stoppages, it covers 9 km less.
Time taken to cover 9 km = (9/54) hour
= (1/6)*60 minutes
= 10 minutes
3. A man in a train notices that he can count 41 telephone posts in one minute. If they are known to be 50 metres apart, then at what speed is the train travelling?
- 60 km/hr
- 100 km/hr
- 110 km/hr
- 120 km/hr
Answer: Option D
Explanation:
Number of gaps between 41 poles = 40
So total distance between 41 poles = 40*50
= 2000 meter = 2 km
In 1 minute train is moving 2 km/minute.
Speed in hour = 2*60 = 120 km/hour
4. A man is walking at the rate of 5 km/hr crosses a bridge in 15 minutes. The length of the bridge is
- 1000 meters
- 1050 meters
- 1200 meters
- 1250 meters
Answer: Option D
Explanation:
We need to get the answer in meters. So we will first of change distance from km/hour to meter/sec by multiplying it with 5/18 and also change 15 minutes to seconds by multiplying it with 60.
\begin{aligned}
Speed = 5* \frac{5}{18} = \frac{25}{18}m/sec \\
Time = 15*60 seconds = 900 seconds \\
Distance = Time * Speed \\
Distance = \frac{25}{18}*900 = 1250 meter
\end{aligned}
5. A person crosses a 600 meter long street in 5 minutes. What is the speed in Km/hr
- 6.2 km/hr
- 7.2 km/hr
- 8.2 km/hr
- 9.2 km/hr
Answer: Option B
Explanation:
Two things to give attention on this question.
First time is in minutes, we need to change it to seconds to get speed in m/sec, then we need to get the final answer in km/hr.
So lets solve this.
\begin{aligned}
Speed = \frac{Distance}{Time} \\
Distance = 650 meter \\
Time = \text{5 minutes} = 300 sec \\
Speed = \frac{600}{300} = 2 m/sec \\
=> 2*\frac{18}{5} km/hr = 7.2 km/hr
\end{aligned}
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