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In a class free notebooks were distributed among all the children. Each child got notebooks which were one-eighth of the number of children. If number of children been half, then each child would have recieved 16 notebooks in total. Find the total number of books distributed.

  • 450
  • 512
  • 598
  • 658

Answer: Option B

Explanation:

Let suppose total number of students in class are X.
Then from the question we can conclude it that,
\begin{aligned}
X*\frac{1}{8}X = \frac{X}{2}*16 \\
=> X = 64\\
\text{Total notebooks,} \\
= \frac{1}{8}X^2 \\
= \left( \frac{1}{8} * 64 * 64 \right) \\
= 512
\end{aligned}

Similar Questions :

1. Value of
\begin{aligned}
\frac{1}{2+\frac{1}{2+\frac{1}{2-\frac{1}{2}}}}

\end{aligned}

  • \begin{aligned} \frac{6}{19} \end{aligned}
  • \begin{aligned} \frac{7}{19} \end{aligned}
  • \begin{aligned} \frac{8}{19} \end{aligned}
  • \begin{aligned} \frac{9}{19} \end{aligned}

Answer: Option C

Explanation:

\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{1}{\frac{3}{2}}}}
\end{aligned}
\begin{aligned}
= \frac{1}{2+\frac{1}{2+\frac{2}{3}}}
\end{aligned}

\begin{aligned}
= \frac{1}{2+\frac{1}{\frac{8}{3}}}
\end{aligned}

\begin{aligned}
= \frac{1}{2+\frac{3}{8}}
\end{aligned}

\begin{aligned}
= \frac{1}{\frac{19}{8}}
\end{aligned}

\begin{aligned}
= \frac{8}{19}
\end{aligned}

2. Simplfy
b - [b -(a+b) - {b - (b - a+b)} + 2a]

  • a
  • 2a
  • 4a
  • 0

Answer: Option D

Explanation:

b-[b-(a+b)-{b-(b-a+b)}+2a]
=b-[b-a-b-{b-(2b-a)}+2a]
=b-[-a-{b-2b+a}+2a]
=b-[-a-{-b+a}+2a]
=b-[-a+b-a+2a]
=b-[-2a+b+2a]
=b-b
=0

3. The number of girls in a class are 7 times the number of boys, which value can never be the of total students

  • 40
  • 48
  • 24
  • 30

Answer: Option D

Explanation:

Let the boys are X, then girls are 7X, total = X+7X = 8X

So it should be multiple of 8, 30 is not a multiple of 8.

4. If a - b = 3 and \begin{aligned} a^2 + b^2 = 29 \end{aligned}, then find the value of ab

  • 7
  • 8.5
  • 10
  • 12

Answer: Option C

Explanation:

Remember the formula, if not then cram it :)
\begin{aligned} 2ab = (a^2 + b^2)- (a-b)^2 \end{aligned}
=> 2ab = 29 - 9 = 20
=> ab = 10

5. Simplify
(31/10) * (3/10) + (7/5) / 20

  • 0
  • 1
  • 10
  • 100

Answer: Option B

Explanation:

= (31/10) * (3/10) + (7/5) / 20
= (3.1) * (.3) + (1.4) / 20
= 0.93 + 0.07
= 1

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