Question Detail

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is

54.48
54.68
54.60
54.58

Answer: Option B

Explanation:

$\begin{aligned} \frac{(55 \times 50) +(60 \times 55) +(45 \times 60) }{55 + 60 + 45} \end{aligned}$

$\begin{aligned} \frac{8750}{160} = 54.68 \end{aligned}$

1. Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is

Answer: Option A

Explanation:

Number is (5*27) - (4*25) = 135-100 = 35

2. The average of four consecutive odd numbers is 24. Find the largest number.

Answer: Option B

Explanation:

Let the numbers are x, x+2, x+4, x+6, then

$\begin{aligned} => \frac{x+(x+2)+(x+4)+(x+6)}{4} = 24 \end{aligned}$

$\begin{aligned} => \frac{4x+12)}{4} = 24 \end{aligned}$

$\begin{aligned} => x+3 = 24 => x = 21 \end{aligned}$

So largest number is 21 + 6 = 27

3. Average of first five multiples of 3 is

Answer: Option A

Explanation:

$\begin{aligned} Average = \frac{3(1+2+3+4+5)}{5} = \frac{45}{5} = 9 \end{aligned}$

4. A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match

Answer: Option D

Explanation:

Let the average after 17th match is x
then the average before 17th match is x-3

so 16(x-3) + 87 = 17x
=> x = 87 - 48 = 39

5. Find the average of first 10 multiples of 7

35.5
37.5
38.5
40.5

Answer: Option C

Explanation:

$\begin{aligned} = \frac {7(1+2+3+...+10)}{10} \end{aligned}$

$\begin{aligned} = \frac {7(10(10+1))}{10 \times 2} \end{aligned}$

$\begin{aligned} = \frac {7(110)}{10 \times 2} = 38.5 \end{aligned}$

Question Detail

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is

1. Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is

2. The average of four consecutive odd numbers is 24. Find the largest number.

3. Average of first five multiples of 3 is

4. A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match

5. Find the average of first 10 multiples of 7

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Question Detail

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, then the average marks of all the students is

1. Average of five numbers is 27. If one number is excluded the average becomes 25. The excluded number is

2. The average of four consecutive odd numbers is 24. Find the largest number.

3. Average of first five multiples of 3 is

4. A batsman makes a score of 87 runs in the 17th match and thus increases his average by 3. Find his average after 17th match

5. Find the average of first 10 multiples of 7

Thanks ! Your comment will be approved shortly !

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