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Question Detail
If A:B = 2:3, B:C = 4:5 and C:D = 6:7, then find the value of A:B:C:D
- 15:24:30:35
- 16:24:30:35
- 17:24:30:35
- 18:24:30:35
Answer: Option B
Explanation:
\begin{aligned}
A:B = 2:3 \\
B:C = 4:5 = (4*\frac{3}{4} : 5*\frac{3}{4}) \\
= 3:\frac{15}{4} \\
C:D = 6:7 = (6*\frac{15}{24} : 7*\frac{15}{24}) \\
= \frac{15}{4}:\frac{35}{8} \\
A:B:C:D = 2:3:\frac{15}{4}:\frac{35}{8} \\
= 16:24:30:35
= 8:12:9
\end{aligned}
1. If 2 : 9 :: x : 18, then find the value of x
- 2
- 3
- 4
- 6
Answer: Option C
Explanation:
Treat 2:9 as 2/9 and x:18 as x/18, treat :: as =
So we get 2/9 = x/18
=> 9x = 36
=> x = 4
2. The sum of three numbers is 98. If the ratio of the first to the second is 2:3 and that of the second to the third is 5:8, then the second number is
- 10
- 17
- 25
- 30
Answer: Option D
Explanation:
\begin{aligned}
a:b = 2:3 \\
b:c = 5:8 = (5*\frac{3}{5} : 8*\frac{3}{5}) \\
= 3:\frac{24}{5} \\
a:b:c = 2:3:\frac{24}{5} \\
= 10:15:24 \\
b = 98*\frac{15}{49} \\
= 30
\end{aligned}
3. If a:b = 2:3 and b:c = 4:3, then find a:b:c
- 8:12:9
- 2:3:8
- 2:3:9
- 2:3:12
Answer: Option A
Explanation:
\begin{aligned}
a:b = 2:3 \\
b:c = 4:3 = (4*\frac{3}{4} : 3*\frac{3}{4}) \\
= 3:\frac{9}{4} \\
a:b:c = 2:3:\frac{9}{4} \\
= 8:12:9
\end{aligned}
4. A dog takes 3 leaps for every 5 leaps of a hare. If one leap of the dog is equal to 3 leaps of the hare, the ratio of the speed of the dog to that of the hare is
- 4:5
- 9:5
- 8:5
- 9:2
Answer: Option B
Explanation:
Dog : Hare = (3*3) leaps of hare : 5 leaps of hare
= 9 : 5
5. In a mixture 60 litres, the ratio of milk and water 2 : 1. If the this ratio is to be 1 : 2, then the quanity of water to be further added is
- 20 liters
- 30 liters
- 50 liters
- 60 liters
Answer: Option D
Explanation:
Quantity of Milk = 60*(2/3) = 40 liters
Quantity of water = 60-40 = 20 liters
As per question we need to add water to get quantity 2:1
=> 40/(20+x) = 1/2
=> 20 + x = 80
=> x = 60 liters
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