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Question Detail
If a - b = 3 and \begin{aligned} a^2 + b^2 = 29 \end{aligned}, then find the value of ab
- 7
- 8.5
- 10
- 12
Answer: Option C
Explanation:
Remember the formula, if not then cram it :)
\begin{aligned} 2ab = (a^2 + b^2)- (a-b)^2 \end{aligned}
=> 2ab = 29 - 9 = 20
=> ab = 10
1. Find the value of X
X = (6/119) * (63/8) * (17/9)
- 1/4
- 2/4
- 3/4
- 4
Answer: Option C
2. If p - q = 3 and
\begin{aligned} p^2 + q^2 = 29 \end{aligned}, find the value of pq.
- 7
- 8
- 9
- 10
Answer: Option D
Explanation:
We know
\begin{aligned} 2ab = (a^2 + b^2) - (a - b)^2 \end{aligned}
\begin{aligned} 2pq = 29 - 9 = 20 \end{aligned}
\begin{aligned} =>pq = 10 \end{aligned}
3. Company workers decided to raise Rs. 3 lakhs by equal contribution from each. Had they contributed Rs. 50 each extra, the contribution would have been Rs. 3.25 lakhs. How many workers were they?
- 300
- 400
- 500
- 600
Answer: Option C
Explanation:
N * 50 = (325000 - 300000) = 25000
N = 25000 / 50
= 500
4. 3034 - (1002 / 20.04) = ?
- 2984
- 2983
- 2982
- 2981
Answer: Option A
5. Simplfy
b - [b -(a+b) - {b - (b - a+b)} + 2a]
- a
- 2a
- 4a
- 0
Answer: Option D
Explanation:
b-[b-(a+b)-{b-(b-a+b)}+2a]
=b-[b-a-b-{b-(2b-a)}+2a]
=b-[-a-{b-2b+a}+2a]
=b-[-a-{-b+a}+2a]
=b-[-a+b-a+2a]
=b-[-2a+b+2a]
=b-b
=0
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