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Question Detail
if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
- 12.039
- 1.2039
- 11.039
- 1.1039
Answer: Option D
Explanation:
Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :
\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}
1. \begin{aligned} \sqrt{0.00059049} \end{aligned}
- 24.3
- 2.43
- 0.243
- 0.0243
Answer: Option D
2. if a = 0.1039, then the value of
\begin{aligned} \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
- 12.039
- 1.2039
- 11.039
- 1.1039
Answer: Option D
Explanation:
Tip: Please check the question carefully before answering. As 3a is not under the root we can convert it into a formula , lets evaluate now :
\begin{aligned}
= \sqrt{4a^2 - 4a + 1} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1)^2 + (2a)^2 - 2x1x2a} + 3a \end{aligned}
\begin{aligned}
= \sqrt{(1-2a)^2} + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= (1-2a) + 3a \end{aligned}
\begin{aligned}
= 1 + a = 1 + 0.1039 = 1.1039 \end{aligned}
3. The least perfect square, which is divisible by each of 21, 36 and 66 is
- 213414
- 213424
- 213434
- 213444
Answer: Option D
Explanation:
L.C.M. of 21, 36, 66 = 2772
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it a perfect square, it must be multiplied by 7 x 11.
So, required number = 2 x 2 x 3 x 3 x 7 x 7 x 11 x 11 = 213444
4. What is the smallest number by which 3600 be divided to make it a perfect cube.
- 450
- 445
- 440
- 430
Answer: Option A
Explanation:
\begin{aligned}
3600 = 2^3 \times 5^2 \times 3^2 \times 2
\end{aligned}
To make it a perfect cube it must be divided by
\begin{aligned}
5^2 \times 3^2 \times 2 = 450
\end{aligned}
5. Evaluate
\begin{aligned} \sqrt[3]{4\frac{12}{125}} \end{aligned}
- \begin{aligned} 1\frac{2}{5} \end{aligned}
- \begin{aligned} 1\frac{3}{5} \end{aligned}
- \begin{aligned} 1\frac{4}{5} \end{aligned}
- 1
Answer: Option B
Explanation:
\begin{aligned}
= \sqrt[3]{\frac{512}{125}} \end{aligned}
\begin{aligned}
= (\frac{8*8*8}{5*5*5})^{\frac{1}{3}} \end{aligned}
\begin{aligned} = \frac{8}{5} = 1\frac{3}{5} \end{aligned}
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