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Question Detail
If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number.
- 2:5
- 2:7
- 5:7
- 5:3
Answer: Option D
Explanation:
Let the first number is A and second number is B.
As per question
\begin{aligned}
\frac{40}{100}A = \frac{2}{3}B \\
\frac{A}{B} = \frac{2}{3}*\frac{100}{40} \\
\frac{A}{B} = \frac{5}{3} \\
=> A:B = 5:3
\end{aligned}
1. Salaries of Ravi and Sumit are in the ratio 2:3. If the salary of each is increased by Rs 4000, the new ratio becomes 40:57. What is Sumit present salary.
- 32000
- 34000
- 38000
- 40000
Answer: Option C
Explanation:
Let the original Salaries of Ravi and Sumit is 2x and 3x.
So as per question
\begin{aligned}
\frac{2x+4000}{3x+4000} = \frac{40}{57} \\
=> 57(2x+4000) = 40(3x+4000) \\
=> 6x = 68000 \\
=> 3x = 34000 \\
\text{ Sumit Salary =} 3x+4000 \\
34000 + 4000 = 38000
\end{aligned}
2. If A:B:C = 2:3:4, then find
\begin{aligned}
\frac{A}{B}:\frac{B}{C}:\frac{C}{A}
\end{aligned}
- 5:9:24
- 6:9:24
- 7:9:24
- 8:9:24
Answer: Option D
Explanation:
Let A = 2x, B = 3x, C = 4x, then,
\begin{aligned}
\frac{A}{B} = \frac{2x}{3x} = \frac{2}{3} \\
\frac{B}{C} = \frac{3x}{4x} = \frac{3}{4} \\
\frac{C}{A} = \frac{4x}{2x} = \frac{2}{1} \\
=> \frac{A}{B}:\frac{B}{C}:\frac{C}{A} \\
= \frac{2}{3}:\frac{3}{4}:\frac{2}{1} \\
= 8:9:24
\end{aligned}
3. If Rs. 782 is divided into three parts, proportional to
\begin{aligned}
\frac{1}{2}:\frac{2}{3}:\frac{3}{4}
\end{aligned}
find the first part.
- 190
- 204
- 220
- 230
Answer: Option B
Explanation:
\begin{aligned}
\frac{1}{2}:\frac{2}{3}:\frac{3}{4} \\
= 6:8:9\\
\text{First part =} 782 * \frac{6}{23} \\
= 204
\end{aligned}
4. If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number.
- 2:5
- 2:7
- 5:7
- 5:3
Answer: Option D
Explanation:
Let the first number is A and second number is B.
As per question
\begin{aligned}
\frac{40}{100}A = \frac{2}{3}B \\
\frac{A}{B} = \frac{2}{3}*\frac{100}{40} \\
\frac{A}{B} = \frac{5}{3} \\
=> A:B = 5:3
\end{aligned}
5. if x:y = 1:3, then find the value of
(7x+3y):(2x+y)
- 14:5
- 15:5
- 16:5
- 17:5
Answer: Option C
Explanation:
let x = 1k and y = 3k, so
\begin{aligned}
= \frac{7(k)+3(3k)}{2(k)+1(3k)} \\
= \frac{16k}{5k} \\
= 16:5
\end{aligned}
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